MCQ
Identify the $D$ and $E$ in the following reaction

$\begin{array}{*{20}{c}}
  {C{H_3} - CH - CH - C{H_3}\xleftarrow[{ether}]{{Na}}R\,' - Br\,\xrightarrow{{Mg}}'D'\,\xrightarrow{{{H_2}O}}E} \\ 
  {\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,\,\,\,\,C{H_3}\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$

  • $'D'\, \to \,\begin{array}{*{20}{c}}
      {C{H_3}\,\,} \\ 
      {|\,\,\,\,\,\,\,\,} \\ 
      {C{H_3} - CH - MgBr} 
    \end{array}$   $,$   $'E'\, \to \,\begin{array}{*{20}{c}}
      {\,\,\,\,\,\,\,\,\,C{H_3}\,\,} \\ 
      {\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,} \\ 
      {C{H_3} - CH - H} 
    \end{array}$
  • B
    $'D'\, \to \,\begin{array}{*{20}{c}}
      {\begin{array}{*{20}{c}}
      {\,\,\,C{H_3}} \\ 
      {|\,\,} 
    \end{array}\,\,} \\ 
      {C{H_3} - C - MgBr} \\ 
      {\,|\,\,\,\,\,} \\ 
      {\,\,C{H_3}} 
    \end{array}$  $,$  $'E'\, \to \,\begin{array}{*{20}{c}}
      {\,\,\,\,\begin{array}{*{20}{c}}
      {\,\,\,C{H_3}} \\ 
      {|\,\,} 
    \end{array}\,\,} \\ 
      {C{H_3} - C - OH} \\ 
      {\,\,\,\,|\,\,\,\,\,} \\ 
      {\,\,\,\,\,\,C{H_3}} 
    \end{array}$
  • C
    $'D'\, \to \,\begin{array}{*{20}{c}}
      {\begin{array}{*{20}{c}}
      {\,\,\,C{H_3}} \\ 
      {|\,\,} 
    \end{array}\,\,} \\ 
      {C{H_3} - C - MgBr} \\ 
      {\,|\,\,\,\,\,} \\ 
      {\,\,C{H_3}} 
    \end{array}$  $,$  $'E'\, \to \,\begin{array}{*{20}{c}}
      {\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
      {\,\,\,C{H_3}} \\ 
      {|\,\,} 
    \end{array}\,\,} \\ 
      {C{H_3} - C - H} \\ 
      {\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
    \end{array}$
  • D
    $'D'\, \to \,\begin{array}{*{20}{c}}
      {C{H_3}\,\,} \\ 
      {|\,\,\,\,\,\,\,\,} \\ 
      {C{H_3} - CH - MgBr} 
    \end{array}$  $,$  $'E'\, \to \,\begin{array}{*{20}{c}}
      {\,\,\,\,\,\,\,\,\,C{H_3}\,\,} \\ 
      {\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,} \\ 
      {C{H_3} - CH - OH} 
    \end{array}$

Answer

Correct option: A.
$'D'\, \to \,\begin{array}{*{20}{c}}
  {C{H_3}\,\,} \\ 
  {|\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - CH - MgBr} 
\end{array}$   $,$   $'E'\, \to \,\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,C{H_3}\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - CH - H} 
\end{array}$
a

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