MCQ
The compound which will give negative iodoform test is
- A$C{H_3}CHO$
- B$C{H_3}C{H_2}OH$
- CIsopropyl alcohol
- ✓Benzyl alcohol
${C_6}{H_5} - C{H_2} - OH\xrightarrow{{NaOH/{I_2}}}{\text{No}}\,\,{\text{yellow}}\,\,ppt.$
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$A_{(s)} + B^+ \to A^+ + B_{(s)} $; $\Delta H^o = -300\,kJ$ is $70\%$.
The standard electrode potential of cell is :- .................... $\mathrm{V}$

${C_6}{H_6}(l)\, + \,\frac{{15}}{2}\,{O_2}(g)\, \to \,6\,C{O_2}(g)\, + \,3{H_2}O\,(g)$
Signs of $\Delta H,\,\Delta S$ and $\Delta G$ for the above reaction will be