MCQ
Identify the electronic configuration of an element whose atomic radii is determined by taking half the internuclear distance between like atoms.
  • $\ce{[He]2s^22p5}$
  • B
    $\ce{[Ar]4s^2}$
  • C
    $\ce{[Ne]3s^2}$
  • D
    $\ce{[Kr]4d^55s^2}$

Answer

Correct option: A.
$\ce{[He]2s^22p5}$
The atomic radii of non $-$ metallic elements are determined by taking half the internuclear distance between like atoms.
The only non $-$ metal in the given options is option $A,$ which is Flourine.

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