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M.C.Q (1 Marks)

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170 questions · auto-graded multiple-choice test.

MCQ 11 Mark
Beryllium shows diagonal relationship with aluminium. Which of the following similarity is incorrect?
  • A
    $\ce{Be_2​C}$ like $\ce{Al_4C_3}$ yields methane on hydrolysis.
  • B
    $\ce{Be},$ like $\ce{Al}$ is rendered passive by $\ce{HNO_3}$ .
  • $\ce{Be(OH)_2}$​ like $\ce{Al(OH)_3}$ is basic.
  • D
    $\ce{Be}$ forms beryllates and $\ce{Al}$ forms aluminate.
Answer
Correct option: C.
$\ce{Be(OH)_2}$​ like $\ce{Al(OH)_3}$ is basic.
Diagonal relationship of $\ce{Be}$ with $\ce{Al}$ is because of small size. $\ce{Be}$ is different from other earth alkaline earth metals.
But it resembles in many of its properties with $\ce{Al}.$ The $\ce{Be(OH)_2}$ and $\ce{Al(OH)_3}$ are amphoteric in nature.
The two structures involve the only movement of electrons and not of atoms or groups, hence these are resonating structures.
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MCQ 21 Mark
The first ionisation potential is maximum for :
  • A
    Lithium
  • B
    Uranium
  • C
    Iron
  • Hydrogen
Answer
Correct option: D.
Hydrogen
Hydrogen experiences the maximum effective nuclear charge. After removal of a electron there will be no electron in the species. Just a nucleus with positive charge will be left which is very unstable. Therefore, ionization potential is maximum for hydrogen.
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MCQ 31 Mark
Which of the following has maximum difference in $1^{st}$ and $2^{nd}$ ionisation enthalpy.
  • $ \ce{1 s^2, 2 s^2, 2 p^6, 3 s^1}$
  • B
    $\ce{1 s^2, 2 s^2, 2 p^6, 3 s^1 }$
  • C
    $ \ce{1 s^2, 2 s^2, 2 p^1} $
  • D
    $ \ce{1 s^2, 2 s^2, 2 p^6} $
Answer
Correct option: A.
$ \ce{1 s^2, 2 s^2, 2 p^6, 3 s^1}$
After losing one electron, it acquires stable electronic configuration, that is why second ionisation enthalpy is very high.
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MCQ 41 Mark
The atomic number of Uut is :
  • $113$
  • B
    $114$
  • C
    $108$
  • D
    $115$
Answer
Correct option: A.
$113$
$\ce{Un − 1; Tri − 3}$. The symbols for these are $\ce{U,T},$ respectively.
Hence for Uut it becomes $113.$
The symbols above mentioned are capital only if they are the first letter otherwise symbols would be small alphabets.
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MCQ 51 Mark
The ionisation energy of nitrogen is more than oxygen because of :
  • A
    More attraction of electrons by the nucleus.
  • The extra stability of half $-$ filled $p\ -$ orbitals.
  • C
    The ionic radius of nitrogen atom is smaller.
  • D
    All of the above are correct.
Answer
Correct option: B.
The extra stability of half $-$ filled $p\ -$ orbitals.
Ionisation energy of nitrogen is more than oxygen due to half $-$ filled $p\ -$ orbitals, which gives it extra stability.
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MCQ 61 Mark
A pair of atomic numbers which belong to $s-$ block are :
  • A
    $7, 15$
  • B
    $6, 12$
  • C
    $9, 17$
  • $3, 12$
Answer
Correct option: D.
$3, 12$
Atomic number $3$ is lithium and it belongs to the $1^{st}$ group.
Atomic number $12$ is magnesium which belongs to the $2^{nd}$ group.
Both $1$ and $2$ groups belong to the $s-$ block.
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MCQ 71 Mark
The period number in the long form of the periodic table is equal to :
  • A
    Magnetic quantum number of any element of the period.
  • B
    Atomic number of any element of the period.
  • Maximum principal quantum number of any element of the period.
  • D
    Maximum azimuthal quantum number of any element of the period.
Answer
Correct option: C.
Maximum principal quantum number of any element of the period.
Period number $=$ maximum $n$ of any element $($where, $n =$ principal quantum number$).$
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MCQ 81 Mark
As we go down in the electro-chemical series of metals, the reactivity ______ .
  • A
    Decreases and then increases
  • B
    Increases and then decreases
  • Decreases
  • D
    Increases
Answer
Correct option: C.
Decreases
Explanation: (C) Decreases
The higher the metal in the series, the more reactive it is and the more vigorously it reacts with water, oxygen and acid. A metal in the activity series can displace any metal below it in the series from its compound. The elements potassium, sodium, lithium and calcium are very reactive and they react with cold water to produce hydroxides and hydrogen gas. The metals above hydrogen are more reactive than hydrogen. These metals can displace hydrogen from acids or water and liberate hydrogen gas. The metals copper, silver gold and platinum are less reactive than hydrogen and they do not replace hydrogen from water or acid.
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MCQ 91 Mark
The chemistry of lithium is very similar to that of magnesium even though they are placed in different groups. Its reason is that :
  • A
    Both are found together in nature.
  • B
    Both have nearly the same size.
  • C
    Both have similar electronic configurations.
  • The ratio of their charge to size is nearly the same.
Answer
Correct option: D.
The ratio of their charge to size is nearly the same.
A Diagonal Relationship is said to exist between certain pairs of diagonally adjacent elements in the second and third periods of the periodic table. These pairs $( \ce{Li, Mg, Be, Al, B, Si}$ etc.$)$ exhibit similar properties; for example, Boron and Silicon are both semiconductors, form halides that are hydrolyzed in water and have acidic oxides.
Such a relationship occurs because crossing and descending the periodic table have opposing effects. On crossing a period of the periodic table, the size of the atoms decreases, and on descending a group the size of the atoms increases. Similarly, on moving along the period the elements become progressively more covalent, less reducing and more electronegative, whereas on descending the group the elements become more ionic, more basic and less electronegative.
Thus, on both descending a group and crossing by one element the changes cancel each other out, and elements with similar properties which have similar chemistry are often found $-$ the atomic size, electronegativity, properties of compounds $($and so forth$)$ of the diagonal members are similar.
The chemistry of lithium is very similar to that of magnesium even though they are placed in different groups. Its reason is that the ratio of their charge to size is nearly the same.
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MCQ 101 Mark
From $\ce{Be}$ to $\ce{Ra},$ ionization energies :
  • A
    Increases
  • Decreases
  • C
    Remain same
  • D
    None of these
Answer
Correct option: B.
Decreases
$\ce{Be}$ to $\ce{Ra},$
As we go down the group in Periodic table, atomic size increase, Nuclear hold on electron decrease for an outer electron.
Thus, Ionization energy decreases down the group.
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MCQ 111 Mark
Outer electronic configuration of $f-$ block elements is :
  • A
    $\ce{(n+1) f^{1-14}(n-1) d^{0-1} n s^2} $
  • B
    $\ce{(n-2) f^{1-14}(n+1) d^{0-1} n s^2} $
  • $\ce{(n-2) f^{1-14}(n-1) d^{0-1} n s^2} $
  • D
    None of the above.
Answer
Correct option: C.
$\ce{(n-2) f^{1-14}(n-1) d^{0-1} n s^2} $
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MCQ 121 Mark
Which of the following is not a noble gas?
  • A
    Helium
  • B
    Xenon
  • Radium
  • D
    Radon
Answer
Correct option: C.
Radium
Helium, xenon and radon are inert gases. Radium is an alkaline earth metal.
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MCQ 131 Mark
$3d-$ transition series of elements starts with scandium which has the electronic configuration:
  • $3d^1 4s^2$
  • B
    $3d^1 4s^1$
  • C
    $3d^2 4s^2$
  • D
    $3d^3 4s^2$
Answer
Correct option: A.
$3d^1 4s^2$
Before the $4p-$ orbital is filled, filling up of $3d-$ orbitals becomes energetically favourable and we come across the so called $3d$ transition series of elements. This starts from scandium $\ce{(Z = 21)}$ which has electronic configuration $\ce{[Ar]3d^1 4s^2}$.
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MCQ 141 Mark
The most reactive metal is:
  • A
    Sodium
  • B
    Magnesium
  • Potassium
  • D
    Calcium
Answer
Correct option: C.
Potassium
C. Potassium

Explanation: Sodium Na and Potassium K are present in the group I that is alkali metal elements. While Magnesium Mg and Calcium Ca are group II alkaline earth metals. As we move from left to right in the periodic table the ionization energy increases as new electrons enter the same shell so, effective nuclear charge increases. So, Na and K are more reactive than Mg and Ca respectively. And as we go down the group number of shells increases so atomic size increases so, ionization energy decreases. As ionization energy decreases the reactivity of metal increases. So, Potassium is the most reactive metal.
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MCQ 151 Mark
Which of the following elements can show covalency greater than $4\ ?$
  • A
    $\ce{Be}$
  • B
    $\ce{Si}$
  • $\ce{S}$
  • D
    $\ce{B}$
Answer
Correct option: C.
$\ce{S}$
$P$ and $S$ have $d-$ orbitals in their valence shell and therefore, can accommodate more than $8.$ electrons in their respective valence shells. Hence they show covalency more than $4.$
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MCQ 161 Mark
A neutral atom of an element has a nucleus with nuclear charge $11$ times and mass $23$ times that of hydrogen. Write the electronic configuration of the element?
  • A
    $2, 1$
  • $2, 8, 1$
  • C
    $2, 8$
  • D
    $2, 8, 8, 3$
Answer
Correct option: B.
$2, 8, 1$
Since the charge of the nucleus is $11$ times that of the hydrogen atom, the number of electrons is $11$ and electronic configuration is $2, 8, 1.$
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MCQ 171 Mark
The element with configuration $\ce{1 s^2, 2 s^2, 2 p^6, 3 s^2}$ would be :
  • A
    A metal
  • B
    A non $-$ metal
  • A inert gas
  • D
    A metalloid
Answer
Correct option: C.
A inert gas
Since, it has two valence electrons, it is a part of alkaline earth metals, therefore, it is a metal.
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MCQ 181 Mark
The ionization energies from $\ce{Ga}$ to $\ce{Tl}$ do not decrease due to :
  • A
    Shielding effect
  • Improper shielding effect.
  • C
    Increase in the atomic size.
  • D
    Decrease in the nuclear charge.
Answer
Correct option: B.
Improper shielding effect.
Due to poor shielding effect of $d$ and $f$ orbitals, which balances the effect of increase in nuclear charge down the group, resulting in unevenness in the trend.
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MCQ 191 Mark
If the bond distance in chlorine molecule $\ce{(Cl_2)}$ is $\ce{198pm},$ then the radius of chlorine is :
  • A
    $\ce{198pm}$
  • B
    $\ce{49.5pm}$
  • $\ce{99pm}$
  • D
    $\ce{24.75pm}$
Answer
Correct option: C.
$\ce{99pm}$
Radius of $\ce{Cl}-$ atom $=\frac{\text{Bond distance in Cl}_2}{2}$
$=\frac{198}{2}=99\text{pm}$
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MCQ 201 Mark
Which of the following will have the most negative and least negative electron gain enthalpy respectively, $\ce{P, S, Cl}$ and $\ce{F}\ ?$
  • A
    $\ce{P}$ and $\ce{Cl}.$
  • B
    $\ce{S}$ and $\ce{Cl.}$
  • C
    $\ce{Cl}$ and $\ce{F}.$
  • $\ce{Cl}$ and $\ce{P}.$
Answer
Correct option: D.
$\ce{Cl}$ and $\ce{P}.$
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MCQ 211 Mark
Which of the following have no unit?
  • Electronegativity.
  • B
    Electron gain enthalpy.
  • C
    Metallic  enthalpy.
  • D
    Lonisation character.
Answer
Correct option: A.
Electronegativity.
A qualitative measure of the ability of an atom in a chemical compound to attract shared electrons to itself is called electronegativity. Unlike ionization enthalpy and electron gain enthalpy, it is not a measureable quantity.
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MCQ 221 Mark
Differentiating electron in $\ce{K(19)}$ goes into ns and this is $s-$ block element. If Aufbau rule is not followed, $\ce{K(19)}$ will be placed in :
  • A
    $s-$ block
  • B
    $p-$ block
  • $d-$ block
  • D
    $f-$ block
Answer
Correct option: C.
$d-$ block
$\ce{K(19)}$ in the absence of Aufbau rule will have $\ce{EC}$ as : $\ce{1 s^2, 2 s^2 2 p^6, 3 s^2 3 p^6 3 d^1}$ and thus differentiating electron enters into $\ce{3d\ d}-$ block element.
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MCQ 231 Mark
Electronic configuration of magnesium is :
  • $2, 8, 2$
  • B
    $2, 8, 1$
  • C
    $2, 8, 7$
  • D
    $2, 1$
Answer
Correct option: A.
$2, 8, 2$
Magnesium has atomic number $12$. It will be distributed in $\ce{K, L, M}$ shell in the following way:
$K$ shell can accommodate a maximum of $2$ electrons.
$L$ shell can accommodate a maximum of $8$ electrons and $M$ shell will accommodate $2$ electrons.
So the configuration becomes $2, 8, 2.$
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MCQ 241 Mark
Mendeleev corrected the atomic weight of :
  • $\ce{Be}$
  • B
    $\ce{N}$
  • C
    $\ce{O}$
  • D
    $\ce{Cl}$
Answer
Correct option: A.
$\ce{Be}$
Mendeleev's periodic table helped in correcting the atomic masses of some of the elements, based on their positions in the periodic table.
For example, the atomic mass of beryllium was corrected from $13.5$ to $9.0$. Atomic masses of indium, gold and platinum were also corrected.
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MCQ 251 Mark
Elements having similar outer shell electronic configuration in their atoms are arranged in :
  • A
    Groups.
  • B
    Vertical columns.
  • C
    Families.
  • All of these.
Answer
Correct option: D.
All of these.
Similar outer configuration in their atoms are arranged in vertical columns called groups or families.
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MCQ 261 Mark
Which of the following types of elements show variable valency?
  • A
    Transition elements.
  • B
    $s-$ block elements.
  • C
    $f-$ block elements.
  • Both $(a)$ and $(c).$
Answer
Correct option: D.
Both $(a)$ and $(c).$
Variable valency is exhibited by transition elements and $f-$ block elements.
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MCQ 271 Mark
The decreasing order of the second ionization potential of $\ce{K, Ca}$ and $\ce{Ba}$ is:
  • $\ce{K > Ca > Ba}$
  • B
    $\ce{Ca > Ba > K}$
  • C
    $\ce{Ba > K > Ca}$
  • D
    $\ce{K > Ba > Ca}$
Answer
Correct option: A.
$\ce{K > Ca > Ba}$
As we move down the group size increases and the electrons experience less effective nuclear charge. Due to this reason, ionization potential decreases down the group. Thus, the second ionization potential of $\ce{Ca}$ is greater than that of $\ce{Ba}.$
The second ionization potential of $\ce{K}$ is greater than that of $\ce{Ca}$ as $\ce{K}$ acquires stable noble gas configuration after losing one electron.
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MCQ 281 Mark
Write the electronic configuration of the $\ce{Ca}^{2+}$ in absence of Aufbau Principle.
 
  • $ \ce{1 s^2, 2 s^2 p^6, 3 s^2 3 p^6} $
  • B
    $ \ce{1 s^2, 2 s^2 2 p^6, 3 s^2 3 p^3 4 d^3} $
  • C
    $ \ce{1 s^2, 2 s^2 2 p^6, 3 s^{23} p^5 4 d^1} $
  • D
    None of these
Answer
Correct option: A.
$ \ce{1 s^2, 2 s^2 p^6, 3 s^2 3 p^6} $
The Aufbau rule states that in the ground state of an atom, an electron enters the orbital with the lowest energy first and subsequent electrons are fed in the order of increasing energies.
The word 'Aufbau' in German means 'building up'. Here, it refers to the filling up of orbitals with electrons.
So the correct configuration is $\ce{1 s^2, 2 s^2 p^6, 3 s^2 3 p^6} $
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MCQ 291 Mark
The elements in which electrons are progressively filled in $\ce{4f}-$ orbital are called :
  • A
    Actinoids.
  • B
    Transition elements.
  • Lanthanoids.
  • D
    Halogens.
Answer
Correct option: C.
Lanthanoids.
The sixth period $\ce{(n = 6)}$ contains $32$ elements and electrons enter $\ce{6s, 4f, 5d}$ and $\ce{6p}$ orbitals, in the order of filling up of the $4f$ orbitals begins with cerium $\ce{(Z = 58)}$ and ends at lutetium $\ce{(Z = 71)}$ to give the $\ce{4f}-$ inner transition series which is called the lanthanoid series.
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MCQ 301 Mark
Recently $($in $2003)$ element with atomic number $110$ has been named by $\ce{IUPAC}$ as :
  • A
    $\ce{Hs}$
  • B
    $\ce{Mt}$
  • $\ce{Ds}$
  • D
    $\ce{Sg}$
Answer
Correct option: C.
$\ce{Ds}$
Element $110$ being named darmstadtium with symbol $\ce{Ds}$ by $\text{IUPAC}.$
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MCQ 311 Mark
What is the electronic arrangement of $\ce{G}\ ?$
  • A
    $2, 2, 5$
  • B
    $2, 4, 3$
  • $2, 7$
  • D
    $2, 5, 2$
Answer
Correct option: C.
$2, 7$
$\ce{G}$ has atomic number $9$. So it has electronic arrangement as $2,7.$
Seven electrons are present in outer shell so it has the highest tendency to receive one electron and complete its octet.
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MCQ 321 Mark
The pair of amphoteric hydroxides is :
  • A
    $\ce{Al(OH)_3, LiOH}$
  • B
    $\ce{Be(OH)_2, Mg(OH)_2}$
  • C
    $\ce{B(OH)_3 ​, Be(OH)_2}$
  • $\ce{Be(OH)_2 , Zn(OH)_2}$
Answer
Correct option: D.
$\ce{Be(OH)_2 , Zn(OH)_2}$
The pair of amphoteric hydroxides is $\ce{Be(OH)_2, Zn(OH)_2}$ ​.
Amphoteric oxides reacts with acids as well as bases.
Beryllium hydroxide is amphoteric in nature due to small size, high electronegativity and high ionisation energy of beryllium.
$\ce{Be(OH)_2 + 2HCl \rightarrow BeCl_2 + 2H_2 ​O}$
$\ce{Be(OH)_2​ + 2NaOH \rightarrow Na_2 ​BeO_2 >​ + 2H_2 ​O}$
The amphoteric behaviour of zinc hydroxide is as shown.
$\ce{Zn(OH)_2 + 2HCl \rightarrow ZnCl_2 ​ + 2H_2 O}$
$\ce{Zn(OH)_2 + 2NaOH \rightarrow Na_2 ZnO_2 ​​ + H_2O}$
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MCQ 331 Mark
Which alkali metal element is the most reactive?
  • A
    Caesium
  • B
    Potassium
  • C
    Lithium
  • Francium
Answer
Correct option: D.
Francium
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MCQ 341 Mark
In general second ionisation enthalpy of an atom will be :
  • Higher than the first ionisation enthalpy.
  • B
    Equal to the first ionisation enthalpy.
  • C
    Higher than the third ionisation enthalpy.
  • D
    Equal to the third ionisation enthalpy.
Answer
Correct option: A.
Higher than the first ionisation enthalpy.
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MCQ 351 Mark
Recently $($in Aug $2003)$ two new elements have been discovered with atomic number :
  • A
    $113, 114$
  • B
    $114, 115$
  • C
    $115, 116$
  • $113, 115$
Answer
Correct option: D.
$113, 115$
Two superheavy elements, elements $113$ and $115,$ were recently synthesized through a collaborative effort between scientists from the Physical and Life Sciences Directorate at the Lawrence Livermore National Laboratory and researchers from the Joint Institute for Nuclear Research at the Flerov Laboratory for Nuclear Reactions in Dubna, Russia.
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MCQ 361 Mark
Refer to the Periodic table and identify a highly reactive metal in the sixth period.
  • $\ce{Cs}$
  • B
    $\ce{W}$
  • C
    $\ce{Os}$
  • D
    $\ce{Ir}$
Answer
Correct option: A.
$\ce{Cs}$
As we move from left to right along a period, metal activity decreases.
So here $"\ce{Cs}\ " \ ($alkali metal$)$ is a highly reactive metal in the sixth period.
All others are $d\ -$ block elements so they are less reactive than $\text{Cs}.$
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MCQ 371 Mark
Consider the isoelectronic species, $ {Na}^{+}, {Mg}^{2+}, {F}^{-}$and ${O}^{2-}$. The correct order of increasing length of their radii is _____________.
  • A
    $\text{F}^{-}<\text{O}^{2-}<\text{mg}^{2+}<\text{Na}^{+}$
  • $\text{Mg}^{2+}<\text{Na}^{+}<\text{F}^{-}<\text{O}^{2-}$
  • C
    $\text{O}^{2-}<\text{F}^{-}<\text{Na}^{+}<\text{mg}^{2+}$
  • D
    $\text{O}^{2-}<\text{F}^{-}<\text{Mg}^{2+}<\text{Na}^{+}$
Answer
Correct option: B.
$\text{Mg}^{2+}<\text{Na}^{+}<\text{F}^{-}<\text{O}^{2-}$
Consider the isoelectronic species, $ {Na}^{+}, {Mg}^{2+}, {F}^{-}$and ${O}^{2-}$. The correct order of increasing length of their radii is $\text{Mg}^{2+}<\text{Na}^{+}<\text{F}^{-}<\text{O}^{2-}$ Explanation: Amongst isoelectronic ions, ionic radii decrease with increase in nuclear charge. $\text{Mg}^{2+}(12)<\text{Na}^{+}(11)<\text{F}{(10)}<\text{O}^{2-}(8)$
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MCQ 381 Mark
The symbol and name according to the $\text{IUPAC}$ system for the element with atomic number $= 120,$ respectively are :
  • Ubn and unbinilium.
  • B
    Ubn and unbiunium.
  • C
    Ubn and unnilbium.
  • D
    Ubn and unnilium.
Answer
Correct option: A.
Ubn and unbinilium.
Atomic number $\ce{(Z) = 120}$
$\ce{IUPAC}$ name $=$ Unbinilium
Symbol $=$ Ubn
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MCQ 391 Mark
The character of the hydroxide of the element $\ce{Al}$ :
  • A
    Acidic
  • B
    Basic
  • C
    Neutral
  • Amphoteric
Answer
Correct option: D.
Amphoteric
Period $3,$ group $13$ element $\ce{Al}$ is a metal so it forms hydroxide as $\ce{Al(OH)}_3$​ which has both acidic and basic properties.
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MCQ 401 Mark
$\ce{Z = 114}$ has been discovered recently. It will belong to which of the following family group and electronic configuration?



 
  • Carbon family $\ce{[R n] 5 f^{14} 6 d^{10} 7 s^2 7 p^2}$
  • B
    Oxygen family $\ce{[R n] 5 f^4 6 d^{10} 7 s^2 7 p^4}$
  • C
    Nitrogen family $\ce{[R n] 5 f^{14} 6 d^{10} 7 s^2 7 p^5}$
  • D
    Halogen family $\ce{[R n] 5 f^{14} 6 d^{10} 7 s^2 7 p^5}$
Answer
Correct option: A.
Carbon family $\ce{[R n] 5 f^{14} 6 d^{10} 7 s^2 7 p^2}$
It belongs to Group $14$ as it has four valence electrons.
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MCQ 411 Mark
Successive filling of $3s$ and $3p$ orbitals give rise to the third period. The number of elements present in this period are :
  • A
    $2$
  • B
    $4$
  • C
    $6$
  • $8$
Answer
Correct option: D.
$8$
Successive filling of $3s$ and $3p\ -$ orbitals give rise to the third period of $8$ elements from sodium to argon.
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MCQ 421 Mark
Boron and silicon resemble chemically. This is due to the equal value of their :
  • A
    Electron affinity
  • B
    Atomic volume
  • Ions polarizing power
  • D
    Nuclear charge
Answer
Correct option: C.
Ions polarizing power
Boron and silicon resemble chemically. This is due to the equal value of their ion's polarizing power.
This chemical resemblance is called diagonal relationship. It is due to similarity in ionic sizes and charge/radius ratio of elements.
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MCQ 431 Mark
Why do elements in the same group have similar physical and chemical properties?
  • A
    Because of same electronic configuration.
  • B
    Because of same number of electrons.
  • C
    Because of same number of protons.
  • Because of same valence electrons.
Answer
Correct option: D.
Because of same valence electrons.
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MCQ 441 Mark
Which important property did Mendeleev use to classify the elements in his periodic table?
  • Atomic weight.
  • B
    Atomic number.
  • C
    Melting point.
  • D
    None of these.
Answer
Correct option: A.
Atomic weight.
Mendeleev's used atomic weight as the basis of classification of elements in the periodic table. He arranged $63$ elements known at that time in the periodic table on the basis of the order of their increasing atomic weights and he placed elements with similar nature in same group.
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MCQ 451 Mark
The horizontal rows and the vertical columns in the periodic table are termed as respectively?
  • Periods, groups.
  • B
    Groups, periods.
  • C
    Series, periods.
  • D
    Family, periods.
Answer
Correct option: A.
Periods, groups.
The horizontal rows $($which Mendeleev's called series$)$ are called periods and the vertical columns, groups.
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MCQ 461 Mark
Which elements is expected to have lowest ionization enthalpy?
  • $\ce{Sr}$
  • B
    $\ce{As}$
  • C
    $\ce{Xe}$
  • D
    $\ce{S}$
Answer
Correct option: A.
$\ce{Sr}$
It has largest atomic size.
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MCQ 471 Mark
Which of the following orders of ionic radius is correctly represented?
  • $ \mathrm{H}^{-}>\mathrm{H}>\mathrm{H}^{+} $
  • B
    $ \mathrm{Na}^{+}>\mathrm{F}^{-}>\mathrm{O}^{2-} $
  • C
    $ \mathrm{F}^{-}>\mathrm{O}^{2-}>\mathrm{Na}^{+} $
  • D
    $ \mathrm{Al}^{3+}>\mathrm{Mg}^2+>\mathrm{N}^{3-}$
Answer
Correct option: A.
$ \mathrm{H}^{-}>\mathrm{H}>\mathrm{H}^{+} $
Radius of a cation is always smaller than that of a neutral atom due to decrease in the number of orbitals whereas, the radius of anion is always greater than cation due to decrease in effective nuclear charge.
Hence, the order given in option $(a)$ is correct.
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MCQ 481 Mark
The order of screening effect of electrons of $\ce{s, p, d}$ and $f$ orbitals of a given shell of an atom on its outer shell electrons is :
  • $\ce{s > p > d > f}$
  • B
    $\ce{f > d > p > s}$
  • C
    $\ce{p < d < s > f}$
  • D
    $\ce{f > p > s > d}$
Answer
Correct option: A.
$\ce{s > p > d > f}$
The effective nuclear charge experienced by a valence electron in an atom will be less than the actural charge on the nucleus because of "Shielding" or "Screening" of the valence electron from the nucleus by the intervening core electrons.
For Example : The $2s$ electron in lithium is shielded from the nucleus by the inner of $1s$ electrons.
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MCQ 491 Mark
Which of the following statements is incorrect?
  • A
    Mendeleev's arranged elements in horizontal rows and vertical columns.
  • Mendeleev's arranged elements in order of their increasing atomic number.
  • C
    Mendeleev's system of classifying elements was more elaborate than that of Lother Meyer.
  • D
    None of the above.
Answer
Correct option: B.
Mendeleev's arranged elements in order of their increasing atomic number.
Mendeleev arranged elements in horizontal rows and vertical columns of table in the order of their increasing atomic weights.
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MCQ 501 Mark
As you go down in a group, the alkali metals become :
  • A
    Brighter
  • B
    Hotter
  • More reactive
  • D
    Less reactive
Answer
Correct option: C.
More reactive
Alkali metals are the elements present in group $1$ in the periodic table.
They are very reactive metals and their reactivity increases as we move down the group from top to bottom because of an increase in the atomic size.
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MCQ 511 Mark
Electronic configurations of four elements $\ce{A, B, C}$ and $D$ are given below :
$A. 1\text{s}^2\ 2\text{s}^2\ 2\text{p}^6$
$B. 1\text{s}^2\ 2\text{s}^2\ 2\text{p}^4$
$C.1\text{s}^2\ 2\text{s}^2\ 2\text{p}^6\ 3\text{s}^1$
$D.1\text{s}^2\ 2\text{s}^2\ 2\text{p}^5$
Which of the following is the correct order of increasing tendency to gain electron:
  • $\ce{A < C < B < D}$
  • B
    $\ce{A < B < C < D}$
  • C
    $\ce{D < B < C < A}$
  • D
    $\ce{D < A < B < C}$
Answer
Correct option: A.
$\ce{A < C < B < D}$
$A – 1\text{s}^2\ 2\text{s}^2\ 2\text{p}^6 – $ Noble gas configuration.
$B – 1\text{s}^2\ 2\text{s}^2\ 2\text{p}^4 – 2$ electrons short of stable configuration.
$C – 1\text{s}^2\ 2\text{s}^2\ 2\text{p}^6\ 3\text{s}^1–$​​​​​​​ Requires one electron to complete $5-$ orbital.
$D – 1\text{s}^2\ 2\text{s}^2\ 2\text{p}^5–$​​​​​​​ Requires one electron to attain noble gas configuration.
Noble gases have no tendency to gain electrons since all their orbitals are completely filled. Thus, element $A$ has the least electron gain enthalpy.
Since element $D$ has one electron less and element $B$ has two electrons less than the corresponding noble gas configuration, hence, element $D$ has the highest electron gain enthalpy followed by element $B$.
Since, element $C$ has one electron in the $5-$ orbital and hence needs one more electron to complete it, therefore, electron gain enthalpy of $C$ is less than that of element $B$. Combining all the facts given above, the electron gain enthalpies of the four elements increase in the order $\ce{A < C < B < D}.$
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MCQ 521 Mark
Anomalous pair among the following is :
  • A
    Boron $-$ silicon
  • B
    Aluminium $-$ nickel
  • C
    Beryllium $-$ indium
  • Cobalt $-$ nickel
Answer
Correct option: D.
Cobalt $-$ nickel
Introduction to Mendeleev's Periodic table:
The pair of the element in the periodic table where the element occurring before has more atomic mass than the later occurring one. It is also considered to be a drawback of Mendeleev’s periodic table.
Reasons of anomalous :
The size of an atom is less
Electronegativity is very high as a result ionization enthalpy increases.
The charge to radius ratio is large.
The below image shows the anomalous pairs of elements in Mendeleev's periodic table;
Discrepancies in Mendeleev's periodic table Chemistry, knowledgeuniverseonline.com
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MCQ 531 Mark
Which of the following is/ are general characteristics of an atom with high electronegativity?
  • A
    Tendency to form positive ions.
  • B
    Small atomic size.
  • C
    High ionisation potential.
  • Both $(b)$ and $(c).$
Answer
Correct option: D.
Both $(b)$ and $(c).$
Electronegativity $\propto$ ionisation potential $\propto\frac{1}{\text{atomic size}}$
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MCQ 541 Mark
During a chemical reaction with water, alkali metal oxide and halogen oxide behave respectively as :
  • A
    Acidic oxide and basic oxide.
  • Basic oxide and acidic oxide.
  • C
    Both are natural oxides.
  • D
    Either $(a)$ or $(b).$
Answer
Correct option: B.
Basic oxide and acidic oxide.
$\text{Na}_2\text{O}+2\text{H}_2\text{O}\rightarrow2\text{NaO}+2\text{H}_2\text{O}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Basic nature}$
$2\text{Cl}_2\text{O}_7+2\text{H}_2\text{O}\rightarrow4\text{HCl}+8\text{O}_2$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Acidic nature}$
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MCQ 551 Mark
Which pair is different from the others?
  • $\ce{Li − Mg}$
  • B
    $\ce{Na − K}$
  • C
    $\ce{Ca − Mg}$
  • D
    $\ce{B − Al}$
Answer
Correct option: A.
$\ce{Li − Mg}$
$\ce{Li − Mg}$ have a diagonal relationship between them i.e. they show various similar properties.
Whereas $\ce{Na − K}$ belongs to Group $- 1, \ce{Ca − Mg}$ belongs to Group $- 2$ while $\ce{B − Al}$ belongs to Group $- 13.$
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MCQ 561 Mark
Ratio of radii of $\ce{K, L, M}$ shells of hydrogen atom is :
  • A
    $1 : 2 : 3$
  • B
    $1:\frac{1}{4}:\frac{1}9{}$
  • $1:4:9$
  • D
    $1:\frac{1}{2}:\frac{1}{3}$
Answer
Correct option: C.
$1:4:9$
Radius of orbit $= 0.529 \times n^2$
Ratio $= 0.529 \times 1^2: 0.529 \times 2^2: 0.529 \times 3^2 = 1:4:9$
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MCQ 571 Mark
The statement that is not correct for periodic classification of elements is :
  • A
    The properties of elements are periodic function of their atomic numbers.
  • B
    Non metallic elements are less in number than metallic elements.
  • For transition elements, the $3d-$ orbitals are filled with electrons after $3p$ orbitals and before $4s-$ orbitals.
  • D
    The first ionisation enthalpies of elements generally increase with increase in atomic number as we go along a period.
Answer
Correct option: C.
For transition elements, the $3d-$ orbitals are filled with electrons after $3p$ orbitals and before $4s-$ orbitals.
For transition elements, the $3d-$ orbitals are filled with electrons after $3p$ and $4s-$ orbitals and before $4p-$ orbitals.
The order of filling the orbitals is.
Is $,\ce{2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, …}$
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MCQ 581 Mark
Which of the following is the correct order of chemical reactivity with water according to electrochemical series?
  • $\ce{K > Mg > Zn > Cu}$
  • B
    $\ce{K > Mg > Cu > Zn}$
  • C
    $\ce{Cu > Zn > K > Mg}$
  • D
    $\ce{Mg > aK > Cu > Zn}$
Answer
Correct option: A.
$\ce{K > Mg > Zn > Cu}$
The correct order for the chemical reactivity with water is $\ce{K > Mg > Zn > Cu}$. This is because, among the given metals, potassium has the most negative standard reduction potential and copper has the highest standard reduction potential.
Metal $K$ $Mg$ $Zn$ $Cu$
Standard reduction potential $(V)$ $-2.95$ $-2.363$ $-1.662$ $+0.340$
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MCQ 591 Mark
Identify the property which does not reflect the periodicity of the elements.
  • A
    Bonding behaviour
  • B
    Electronegativity
  • C
    Ionization potential
  • Neutron $-$ proton ratio
Answer
Correct option: D.
Neutron $-$ proton ratio
Neutron to proton ratio is not a periodic property as it is not having any regular trend where as the remaining options have a regular trend in groups as well as periods.
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MCQ 601 Mark
Which group of elements does not show diagonal relationship?
  • A
    $\ce{Li, Mg}$
  • B
    $\ce{Be, Al}$
  • C
    $\ce{B, Si}$
  • $\ce{C, P}$
Answer
Correct option: D.
$\ce{C, P}$
In addition to horizontal and vertical trends, there is a diagonal relationship between elements such as $\ce{Li}$ and $\ce{Mg, Be}$ and $\ce{Al, B}$ and $\ce{Si}$.
A diagonal relationship is said to exist between certain pairs of diagonally adjacent elements in the second and third periods of the periodic table.
But $\ce{C,P}$ doesn't show diagonal relationship.
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MCQ 611 Mark
In Mendeleev's periodic table, gaps were left for the elements to be discovered later. Which of the following elements found a place in the periodic table later?
  • Germanium
  • B
    Chlorine
  • C
    Oxygen
  • D
    Silicon
Answer
Correct option: A.
Germanium
Chlorine, oxygen and silicon were included in Mendeleev's periodic table. Germanium was discovered later which fit into the empty spaces left by Mendeleev and matched to the expected properties.
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MCQ 621 Mark
Which group of elements could be placed in Mendeleev's Periodic Table without disturbing the original order?
  • A
    Alkali metals
  • B
    Alkaline earth metals
  • C
    Non $-$ metals
  • Noble gases
Answer
Correct option: D.
Noble gases
According to Mendeleevs classification, the properties of elements are the periodic function of their atomic masses and there is a periodic recurrence of elements with similar physical and chemical properties.
Noble gas being inert, could be placed in a separate group without disturbing the original order.
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MCQ 631 Mark
Out of the four blocks in which periodic table is divided, helium belongs which block?
  • A
    $s-$ block.
  • $p-$ block.
  • C
    $d-$ block.
  • D
    $f-$ block.
Answer
Correct option: B.
$p-$ block.
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MCQ 641 Mark
Which of the following is the correct order of size of the given species :
  • A
    $\text{I} > \text{I}{^{-}} > \text{I}^+$
  • B
    $\text{I}^+ > \text{I}{^{-}} > \text{I}$
  • C
    $\text{I} > \text{I}{^{+}} > \text{I}^-$
  • $\text{I}^- > \text{I} > \text{I}^+$
Answer
Correct option: D.
$\text{I}^- > \text{I} > \text{I}^+$
Anion is bigger than the parent atom and cation is smaller than the parent atom.
Thus, $\text{I}^- > \text{I} > \text{I}^+$
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MCQ 651 Mark
$\ce{IP}$ values of an element $'X\ '$ are $\ce{104kJ, 200kJ, 420kJ, 2825kJ}$ per mole. Identify the group to which the element belongs?
  • A
    $\ce{IA}$
  • B
    $\ce{IIA}$
  • $\ce{IIIA}$
  • D
    $\ce{IVA}$
Answer
Correct option: C.
$\ce{IIIA}$
As there is large jump from $3^{rd}$ to $4^{th} \ \ce{IP}$ value, the valency of $'X\ '$ would be $3.$
The group number is equal to the valency.
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MCQ 661 Mark
From the following, identify least reactive element :
  • A
    $\ce{{ }_8 Y^{16}}$
  • $\ce{{ }_{10} Y^{20}}$
  • C
    $\ce{{ }_{11} Y^{23}}$
  • D
    $\ce{{ }_9 Y^{19}}$
Answer
Correct option: B.
$\ce{{ }_{10} Y^{20}}$
Element,$\ce{{ }_{10} Y^{20}}$ has the electronic configuration as $2, 8$ has completely filled valence shell.
So, it is least reactive.
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MCQ 671 Mark
State the electronic configuration for Nitrogen $\ce{[p = 7, n = 7].}$
  • A
    $2, 3$
  • B
    $2, 4$
  • C
    $2, 6$
  • $2, 5$
Answer
Correct option: D.
$2, 5$
As we know, atomic no. is the total no of proton present in nucleus of an atom and atomic mass no is the total no of proton and neutron.
So nitrogen have atomic no. $7$ and mass no. $7 + 7 = 14. K$ shell will accommodate $2$ electrons and rest will be accommodated in $L$ shell.
Therefore, the configuration is $2, 5.$
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MCQ 681 Mark
Diagonal relationship is shown by :
  • A
    $\ce{B−S}$
  • $\ce{Li−Mg}$
  • C
    $\ce{Mg−Ca}$
  • D
    $\ce{S−Se}$
Answer
Correct option: B.
$\ce{Li−Mg}$
As we move across the period, the size of atoms decreases and as we move down the group, the size of the atoms gradually increases. The diagonal relationship is due to the similarity in size of the atoms.
Diagonal relationship in the periodic table.
What is the Diagonal Relationship in the Periodic Table? Explain with few Examples
For example, Boron and silicon are both semiconductors that generate halides that are hydrolysed in water and have acidic oxides.
Therefore, Diagonal relationship is shown by $\ce{Li−Mg}.$
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MCQ 691 Mark
Arrange the following elements in order of their increasing ionization energies $\ce{O, S, Se, Te, Po}.$
  • A
    $\ce{Se, Te, S, Po, O}$
  • B
    $\ce{O, S, Se, Te, Po}$
  • $\ce{Po, Te, Se, S, O}$
  • D
    $\ce{Te, O, S, Po, Se}$
Answer
Correct option: C.
$\ce{Po, Te, Se, S, O}$
Ionization energy decreases from top to bottom in a group due to increase in the size of atom.Due to increase in size of atom its ionization energy decreases from top to bottom,
So increasing order will be $\ce{Po}$
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MCQ 701 Mark
The $100^{th}$ element is named in honor of :
  • A
    Einstein
  • B
    Bohr
  • Fermi
  • D
    Curie
Answer
Correct option: C.
Fermi
The $100^{th}$ element is 'Fermium'.
It is named in honor of Scientist Fermi.
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MCQ 711 Mark
Which of the following sets contain only isoelectronic ions?
  • A
    $\text{Zn}^{2+},\text{ Ca}^{2+},\text{ Ga}^{3+},\text{ Al}^{3+}$
  • $\text{K}^+,\text{ Ca}^{2+},\text{ Sc}^{3+},\text{ Cl}^{-}$
  • C
    $\text{P}^{3-},\text{ S}^{-},\text{ Cl}^{-},\text{ K}^{+}$
  • D
    $\text{Ti}^{4+},\text{ Ar},\text{ Cr}^{3+},\text{ V}^{5+}$
Answer
Correct option: B.
$\text{K}^+,\text{ Ca}^{2+},\text{ Sc}^{3+},\text{ Cl}^{-}$
$a. \mathrm{Zn}^{2+}(30-2=28), \mathrm{Ca}^{2+}(20-2=18), \mathrm{Ga}^{3+}(31-3=28), \mathrm{Al}^{3+}(13-3=10)$ are not isoelectronic.
$b. \mathrm{K}^{+}(19-1=18), \mathrm{Ca}^{2+}(20-2=18), \mathrm{Sc}^{3+}(21-3=18), \mathrm{Cl}^{-}(17+1=18)$ are isoelectronic.
$c. \mathrm{P}^{3-}(15+3=18), \mathrm{S}^{-}(16+1=17), \mathrm{Cl}^{-}(17+1=18), \mathrm{K}^{+}(19-1=18)$ are not isoelectronic.
$d. \mathrm{Ti}^{4+}(22-4=18), \mathrm{Ar}(18), \mathrm{Cr}^{3+}(24-3=21), \mathrm{V}^{5+}(23-5=18)$ are not isoelectronic.
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MCQ 721 Mark
The factors that influence the ionisation energies are :
  • A
    The size of the atom
  • B
    The charge on the nucleus
  • C
    How effectively the inner electron shell screen the nuclear charge.
  • All of the above
Answer
Correct option: D.
All of the above
Factors affecting ionisation potential :
Atomic size : Larger the atomic size, smaller is the ionisation potential. It is due to that the size of atom increases the outermost electrons e farther away from the nucleus and nucleus loses the attraction on that electrons and hence can be easily removed.
Effective nuclear charge $\ce{(Z_{eff​})}$ : Ionisation potential increases with the increase in nuclear charge between outermost electrons and nucleus.
Screening effect : Higher is the screening effect on the outer most electrons causes less attraction from the nucleus and can be easily removed, which is leading to the lower value of ionisation potential. Penetration power of sub shells and Stability of half filled and fully filled orbitals.
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MCQ 731 Mark
Half the internuclear distance separating the metal cores in the metallic crystal is termed as :
  • Metallic radius.
  • B
    Atomic radius.
  • C
    Covalent radius.
  • D
    Ionic radius.
Answer
Correct option: A.
Metallic radius.
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MCQ 741 Mark
The given reaction, $\ce{X(g) + e^- \rightarrow X^-(g)}$ is an example of :
  • Electron gain enthalpy.
  • B
    Electron loss enthalpy.
  • C
    Ionisation enthalpy.
  • D
    Both $(a)$ and $(c).$
Answer
Correct option: A.
Electron gain enthalpy.
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MCQ 751 Mark
Which one of the following arrangement represents the correct order of electron gain enthalpy of the given atomic species?
  • A
    $\ce{Cl < F < S < O}$
  • $\ce{S < O < F < Cl}$
  • C
    $\ce{S < O < Cl < F}$
  • D
    $\ce{F < Cl < O < S}$
Answer
Correct option: B.
$\ce{S < O < F < Cl}$
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MCQ 761 Mark
The properties of $ ......... $ were predicted by Mendeleev before their isolation.
  • A
    $\ce{Co}$ and $\ce{Ni}$
  • B
    $\ce{I}$ and $\ce{Te}$
  • $\ce{Sc, Ga}$ and $\ce{Ge}$
  • D
    $\ce{Cl, Ar}$ and $\ce{K}$
Answer
Correct option: C.
$\ce{Sc, Ga}$ and $\ce{Ge}$
ev has the foresight to leave some gaps in the periodic table for $3$ elements and these elements are discovered later and included in the table.
Those three elements are :
Eka $-$ boron is presently known as scandium $\ce{(Sc)}.$
Eka $-$ silicon is presently known as germanium $\ce{(Ge)}.$
Eka $-$ aluminium is presently known as gallium $\ce{(Ga)}$.
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MCQ 771 Mark
A sudden jump between the values of second and third ionization energies of an atom would be associated with the electronic configuration:
 
  • A
    $ 1 s^2, 2 s^2, 2 p^6 $
  • B
    $ 1 s^2, 2 s^2, 2 p^6, 3 s^2, 3 p^1 $
  • C
    $ 1 s^2, 2 s^2, 2 p^6, 3 s^2, 3 p^2 $
  • $1 s^2, 2 s^2, 2 p^6, 3 s^2 $
Answer
Correct option: D.
$1 s^2, 2 s^2, 2 p^6, 3 s^2 $
Magnesium $1 s^2, 2 s^2, 2 p^6, 3 s^2 $ is in group $2$ of the Periodic Table and has first ionisation energy $737.7\ \text{kJ/mol}$, second ionisation energy $1450.7\ \text{kJ/mol}$ and third ionisation energy $7732.7\ \text{kJ/mol.}$
Here the big jump occurs after the second ionisation energy. It means that there are $2$ electrons which are relatively easy to remove the $3s^2$ electrons, while the third one is much more difficult because it comes from an inner level $-$ closer to the nucleus and with less screening.
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MCQ 781 Mark
In the $\ce{P^{3-}, S^{2-}}$ and $\ce{Cl}^-$ ions, the increasing order of size is :
  • $ \mathrm{Cl}^{-}, \mathrm{S}^{2-}, \mathrm{P}^{3-} $
  • B
    $ \mathrm{P}^{3-}, \mathrm{S}^{2-}, \mathrm{Cl}^{-} $
  • C
    $ \mathrm{S}^{2-}, \mathrm{Cl}^{-}, \mathrm{P}^{3-} $
  • D
    $ \mathrm{S}^{2-}, \mathrm{P}^{3-}, \mathrm{Cl}^{-} $
Answer
Correct option: A.
$ \mathrm{Cl}^{-}, \mathrm{S}^{2-}, \mathrm{P}^{3-} $
In Isoelectronic species, higher the nuclear charge, smaller the size.
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MCQ 791 Mark
Considering the elements $\ce{F, Cl, O}$ and $\ce{N}$ the correct order of their chemical reactivity in terms of oxidizing property is :
  • A
    $\ce{F > Cl > O > N}$
  • $\ce{F > O > Cl > N}$
  • C
    $\ce{Cl > F > O > N}$
  • D
    $\ce{O > F > N > Cl}$
Answer
Correct option: B.
$\ce{F > O > Cl > N}$
Considering the elements $\ce{F, Cl, O }$ and $\ce{N},$ the correct order of their chemical reactivity in terms of oxidizing property is $\ce{F > O > Cl > N}.$
$\ce{N, O}$ and $\ce{F}$ are present in the same period. On moving from left to right in a period, the oxidizing power generally increases.
$\ce{F}$ and $\ce{Cl}$ are present in the same group.
On moving from top to bottom in a group, the oxidizing power generally decreases.
Oxidizing property of $\ce{O}$ is more than $\ce{Cl}.$
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MCQ 801 Mark
An atom of an element has one electron in the valence shell. It can be represented as :
  • A
    $ \ce{{ }_6 A^{12}} $
  • $\ce{{ }_{19} A^{39}} $
  • C
    $\ce{{ }_{13} A^{27}} $
  • D
    $ \ce{{ }_{12} A^{24}} $
Answer
Correct option: B.
$\ce{{ }_{19} A^{39}} $
The atomic no. of $ \ce{{ }_6 A^{12} }$ is $6$. Its electronic configuration is $\ce{1s^22s^22p^2}$. It has $4$ electrons in valence shell.
The atomic no. of ${ }_{19} A^{39} $​ is $19.$ Its electronic configuration is $\ce{1s^22s^22p^63s^23p^64s}^1$. It has $1$ electron in valance shell.
The atomic no. of $ { }_{13} A^{27} $​ is $13$. Its electronic configuration is $\ce{1s^22s^22p^63s^23p}^1$. It has $3$ electrons in valence shell.
The atomic no. of $\ce{ { }_{12} A^{24}}$ is $12$. Its electronic configuration is $1\ce{ s^22s^22p^63s^2}$. It has $2$ electrons in valence shell.
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MCQ 811 Mark
Which of the following properties is inversely related to electronegativity?
  • A
    Non $-$ metallic properties.
  • B
    Metalloid properties.
  • C
    Ionic properties.
  • Metallic properties.
Answer
Correct option: D.
Metallic properties.
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MCQ 821 Mark
An element which is an essential constituent of all organic compounds belongs to :
  • A
    group $1$
  • group $14$
  • C
    group $15$
  • D
    group $16$
Answer
Correct option: B.
group $14$
The element which is an essential constituent of all organic compounds is carbon.
It has the electronic configuration $(2, 4)$. It is found in group $14.$
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MCQ 831 Mark
The correct order of electronegativity of $\ce{Na, O}$ and $\ce{F}$ is :
  • A
    $\ce{Na > O > F}$
  • B
    $\ce{O > F > Na}$
  • C
    $\ce{O > Na > F}$
  • $\ce{F > O > Na}$
Answer
Correct option: D.
$\ce{F > O > Na}$
The order of $\ce{EN}$ of $\ce{Na, O}$ and $\ce{F}$ is $\ce{F > O > Na}.$
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MCQ 841 Mark
Predict the position of an element having the electronic configuration $\ce{1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 3 d^5 4 s^1}$.
  • Period $4,$ group $6.$
  • B
    Period $6,$ group $4.$
  • C
    Period $3,$ group $1.$
  • D
    Period $4,$ group $5$.
Answer
Correct option: A.
Period $4,$ group $6.$
$n = 4$ hence, element lies in $4^{th}$ period.
Group $= \ce{ns + (n - 1)d = 1 + 5 = 6.}$
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MCQ 851 Mark
To which block is an element, having electronic configuration $\ce{1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 3 d^{10} 4 s^1,}$ related in the periodic table?
  • A
    $s−$ block
  • B
    $p−$ block
  • $d−$ block
  • D
    $f−$ block
Answer
Correct option: C.
$d−$ block
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MCQ 861 Mark
Which of the following groups of elements have highly negative electron gain enthalpy?
  • A
    Group $-16$
  • B
    Group $-17$
  • C
    Group $-14$
  • Both $(a)$ and $(b).$
Answer
Correct option: D.
Both $(a)$ and $(b).$
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MCQ 871 Mark
Considering the chemical properties, atomic weight of $\ce{Be}$ was corrected based on :
  • A
    Electronic configuration
  • Valency
  • C
    Atomic number
  • D
    Both $B$ and $C$
Answer
Correct option: B.
Valency
The atomic weight of $\ce{Be}$ was corrected based on :
Atomic weight $=$ equivalent weight $\times $ valency
From this, we can understand that the atomic weight of $\ce{Be}$ was corrected based on valency.
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MCQ 881 Mark
The element $119$ has not been discovered. What would be the symbol for this element?
  • $\ce{Uue}$
  • B
    $\ce{UUe}$
  • C
    $\ce{UUE}$
  • D
    None of these
Answer
Correct option: A.
$\ce{Uue}$
Ununennium is also known as eka $-$ francium or simply element $119$.
It is a hypothetical chemical element with the atomic number $119$. Its symbol is $\ce{Uue}.$
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MCQ 891 Mark
Atomic weight of which set of elements were corrected by Mendeleev?
  • A
    $\ce{Li, Na, K}$
  • $\ce{U, Be, In}$
  • C
    $\ce{Tc, Sc, Al}$
  • D
    None of the these
Answer
Correct option: B.
$\ce{U, Be, In}$
Mendeleev corrected atomic weights of Uranium, Beryllium, and Indium $\ce{(U, Be, In)}$ based on their positions in the periodic table. Along with that he also corrected the atomic weights of Gold $\ce{(Au)}$ and Platinum $\ce{(Pt).}$
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MCQ 901 Mark
The ability of an atom in a chemical compound to attract shared electron is termed as :
  • A
    Electron affinity.
  • B
    Ionisation enthalpy.
  • C
    Atomic attraction.
  • Electronegativity.
Answer
Correct option: D.
Electronegativity.
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MCQ 911 Mark
General outer electronic configuration of $d-$ block elements is :
  • A
    $ \ce{(n-1) d^{1-10} n s^3} $
  • B
    $\ce{(n+1) d^{1-10} n s^{0-2}} $
  • $ \ce{(n-1) d^{1-10} n s^{0-2}} $
  • D
    $ \ce{(n-1) d^0 n s^{0-2}} $
Answer
Correct option: C.
$ \ce{(n-1) d^{1-10} n s^{0-2}} $
$d-$ block elements are elements of group $3$ to $12$ in the centre of the periodic table.
So, general outer electronic configuration $= \ce{(n - 1)d^{1-10} ns}^{0-2}$.
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MCQ 921 Mark
The noble gases are nonreactive because :
  • A
    They react with sodium.
  • They have a full outer shell of electrons.
  • C
    They have a half outer shell of neutrons.
  • D
    They are too thin.
Answer
Correct option: B.
They have a full outer shell of electrons.
They have $8$ electrons in their outermost shell $($except He which has $2$ electrons$)$. Therefore, their valency is zero and they are nonreactive as they can neither add nor donate electrons to react.
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MCQ 931 Mark
First ionization potential of $\ce{Mg}$ is less than that of :
  • A
    $\ce{Li}$
  • B
    $\ce{Na}$
  • C
    $\ce{Ca}$
  • $\ce{Be}$
Answer
Correct option: D.
$\ce{Be}$
First $\ce{I.E}$ of $\ce{Mg}$ is greater than that of $\ce{Na}\ ($because of the higher nuclear charge on $\ce{Mg})$ and also that of $\ce{Li.}$ Due to lts larger size, $\ce{Ca}$ has lower $\ce{I.P}$ than $\ce{Mg}. \ce{Be}$ has smaller size than $\ce{Mg}$. Hence $\ce{Be}$ has greater first $\ce{I.P}$ than $\ce{Mg}.$
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MCQ 941 Mark
Diagonal relationship is quite pronounced in the elements of :
  • $2^{nd}$ and $3^{rd}$ periods
  • B
    $1^{st}$ and $2^{nd}$ periods
  • C
    $\ce{II}$ and $\ce{III}$ groups
  • D
    $3^{rd}$ and $4^{th}$ periods
Answer
Correct option: A.
$2^{nd}$ and $3^{rd}$ periods
A diagonal relationship exists between certain pairs of diagonally adjacent elements in the second and third periods of the periodic table.
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MCQ 951 Mark
State the electronic configuration for Helium $\ce{[p = 2, n = 2]}.$
  • A
    $1$
  • B
    $3, 2$
  • $2$
  • D
    $2, 4$
Answer
Correct option: C.
$2$
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MCQ 961 Mark
In which of the following, which of the following is incorrect :
  • $\ce{I < Br < Cl < F}\ ($increasing electron gain enthalpy$)$
  • B
    $\ce{Li < Na < K < Rb}\ ($increasing metallic radius$)$
  • C
    $\ce{Al < Mg < Na < F}\ ($ increasing ionic size$)$
  • D
    $\ce{B < C < O < N}\ ($increasing first ionisation enthalpy$)$
Answer
Correct option: A.
$\ce{I < Br < Cl < F}\ ($increasing electron gain enthalpy$)$
It is incorrect because $'F\ ' $ has lower electron gain enthalpy than $\ce{Cl}.$
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MCQ 971 Mark
The nature of normal oxide formed by the element present on extreme left in the periodic table is :
  • A
    Most acidic.
  • Most basic.
  • C
    Amphoteric.
  • D
    Neutral.
Answer
Correct option: B.
Most basic.
The normal oxide formed by the element present on the extreme left of periodic table is the most basic, e.g. $\ce{Na_2O.}$
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MCQ 981 Mark
Predict the formula of a compound formed between a metal $'M\ '$ which has $1^{st}, 2^{nd}, 3^{rd}\ \ce{IP}$ values as $518, 7314, 9820KJ$ mol $^{-1}$ respectively and a halogen $'X\ '.$
  • A
    $\ce{MX_2}$
  • B
    $\ce{M_2vX_3}$
  • C
    $\ce{MX_3}$
  • $\ce{MX}$
Answer
Correct option: D.
$\ce{MX}$
Alkali metals have low first ionization energies and relatively higher second and third ionization energies because the electron have to be remover from a stable octet.
As in the given question, there is more difference in the values of first and second ionization energies i.e. the metal has $1$ valence electron,
$\therefore$ formula of the compound will be $\ce{MX}.$
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MCQ 991 Mark
Those elements impart colour to the flame on heating in it, the atoms of which require low energy for the ionisation $($i.e., absorb energy in the visible region of spectrum$)$. The elements of which of the following groups will impart colour to the flame?
  • $2$
  • B
    $13$
  • C
    $15$
  • D
    $17$
Answer
Correct option: A.
$2$
The elements of first and second groups, i.e., alkali and alkaline earth metals possess low ionization energies and impart colour to the flame.
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MCQ 1001 Mark
Metal which emits photo $-$ electrons very easily is :
  • A
    $\ce{Al}$
  • B
    $\ce{K}$
  • C
    $\ce{Cs}$
  • $\ce{Cu}$
Answer
Correct option: D.
$\ce{Cu}$
Among the given metals, Caesium has the lowest ionization enthalpy.
Hence, it loses electrons readily.
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MCQ 1011 Mark
Ionization potential value of $\ce{Cs}$ is equal to the electron affinity value of its corresponding $ .........$
  • A
    $\ce{Cs}$
  • $\ce{Cs}^+$
  • C
    $\ce{Cs}^2$+
  • D
    $\ce{Cs}^-$
Answer
Correct option: B.
$\ce{Cs}^+$
Ionization Potential is defined as energy required to remove electron where as $\ce{E}$. A is defined as energy released in adding an electron.
If we remove an electron from $\ce{Cs}$ it becomes $\ce{Cs}^+$.If we add an electron to $\ce{Cs}^+$ then it becomes $\ce{Cs}.$
Hence adding electron to $\ce{Cs}^+$ is electron affinity where other is $\ce{I.P}$ both are reaching the same point.
Hence Ionization potential value of $\ce{Cs}$ is equal to the electron affinity value of its corresponding $\ce{Cs}^+$.
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MCQ 1021 Mark
Which is incorrect configuration for $s-$ block elements?
  • A
    $\ce{[Ar]3d^{10}4s^2}$
  • B
    $\ce{[Ar]3d^{10}4s^1}$
  • Both $A$ and $B$
  • D
    None of these
Answer
Correct option: C.
Both $A$ and $B$
$\ce{[Ar]3d^{10}4s^2} - $ Last filling electron is in $3d.$
$\ce{[Ar]3d^{10}4s^1}-$  Last filling electron is in $3d.$
Thus, both are $d-$ block element.
$\ce{[Ar]4s^{1-2}}$ is a configuration of $s-$ block.
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MCQ 1031 Mark
Identify the least stable ion amongst the following :
  • A
    $\ce{Li}^-$
  • B
    $\ce{Be}^-$
  • $\ce{B}^-$
  • D
    $\ce{C}^-$
Answer
Correct option: C.
$\ce{B}^-$
The configuration of $\ce{Li}$ is $\ce{1s^22s^1}$. Adding one $\ce{e}^-$ will fill its $2s$ subshell providing it extra stability.
The configuration of $\ce{Be}$ is $\ce{1s^22s^2}$. Adding one $\ce{e}^-$ will disturb its stable fully filled configuration. So, it is the least stable among all.
The configuration of $B$ is $\ce{1s^22s^22p^1}$. It does not have half $-$ filled or fully filled configuration so adding one $e^-$ will not disturb its stable configuration.
The configuration of $C$ is $\ce{1s^22s^22p^2}$. It does not have half $-$ filled or fully filled configuration so adding one $e^-$ its configuration becoes $\ce{1s^22s^22p}^3$ that it is a half $-$ filled configuration and becomes stable.
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MCQ 1041 Mark
Which element is considered radioactive among the options given below?
  • A
    Sodium
  • B
    Gold
  • Thorium
  • D
    Neon
Answer
Correct option: C.
Thorium
An element subject to spontaneous degeneration of its nucleus accompanied by the emission of alpha particles, beta particles, or gamma rays. All elements with atomic numbers greater than $83$ are radioactive.
Naturally occurring radioactive elements include radium, thorium, and uranium. Several radioactive elements not found in nature have been produced by the bombardment of stable elements with subatomic particles in a cyclotron.
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MCQ 1051 Mark
Which of the following electronic configurations is characteristic of alkali metals?
  • A
    $(\text{n}−1)\text{p}^6,\text{ns}^2,\text{np}^1$
  • B
    $(\text{n}−1)\text{s}^2\text{p}^6\text{d}^{10},\text{ns}^1$
  • $(\text{n}−1)\text{p}^6,\text{ns}^1$
  • D
    $\text{ns}^2,\text{np}^6,\text{nd}^1$
Answer
Correct option: C.
$(\text{n}−1)\text{p}^6,\text{ns}^1$
The outer most shell electronic configuration of alkali metals $(\ce{IA}$ group elements$)$ is $\ce{ns}^1$. $s-$ block is filled after $p-$ block of the penultimate shell. Some of the electronic configurations of alkali metals are as follows :
$ \ce{Li =1 s^2 2 s^1}$
$\ce{Na =1 s^2 2 s^2 2 p^6 3 s^1} $
$\ce{K =1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 4 s^1} $
$ \ce{Rb =1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 4 s^2 3 d^{10} 4 p^6 5 s^1} $
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MCQ 1061 Mark
Elements are classified into four blocks like $s-$ block $, p-$ block, $d-$ block and $f-$ block on the basis of :
  • A
    Atomic number.
  • B
    Atomic mass.
  • Atomic orbitals.
  • D
    All of these.
Answer
Correct option: C.
Atomic orbitals.
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MCQ 1071 Mark
In second period of periodic table, ionization enthalpy follows the order.
  • A
    $\ce{Ne > F > O > N > C > B > Be > Li}$
  • B
    $\ce{Ne > F > N > C > O > Be > B > Li}$
  • C
    $\ce{Li > B > Be > C > O > N > F > Ne}$
  • $\ce{Ne > F > O > N > C > B > Be > Li}$
Answer
Correct option: D.
$\ce{Ne > F > O > N > C > B > Be > Li}$
$\ce{Ne}$ has stable electronic configuration, $'N\ '$ has half filled $2p\ -$ orbitals and $\ce{Be
}$ has completely filled $2s$ orbitals.
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MCQ 1081 Mark
Arrange $\ce{Be, Ca, Ba, Ra}$ in increasing order of ionisation energy :
  • A
    $\ce{Be < Ra < Ca < Ba}$
  • B
    $\ce{Ba < Ca < Ra < Be}$
  • $\ce{Ra < Ba < Ca < Be}$
  • D
    $\ce{Ba < Ra < Ca < Be}$
Answer
Correct option: C.
$\ce{Ra < Ba < Ca < Be}$
Atomic number of Beryllium $-\ 4$
Atomic number of Calcium $-\ 20$
Atomic number of Barium $-\ 56$
Atomic number of Radium $-\ 88$
From the atomic numbers, we can easily say that Beryllium is the starting element in $\ce{II A}$ group and Radium is the last element in $\ce{II A}$ group.
We know that as we are moving from top to bottom in the periodic table the atomic size of the atoms increases.
So, the increasing order of ionization energy of given elements is as follows. $\ce{Ra < Ba < Ca < Be}.$
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MCQ 1091 Mark
Which of the following is mismatched with reference to third period?
  • A
    Largest size $-$ Argon.
  • B
    Strongest oxidant $-$ chlorine.
  • $\ce{IP}$ of phosphorus $-$ greater than nitrogen.
  • D
    $\ce{IP}$ of phosphorus $-$ greater than sulphur.
Answer
Correct option: C.
$\ce{IP}$ of phosphorus $-$ greater than nitrogen.
$\ce{IP}$ of phosphorus is not greater than nitrogen because half $-$ filled orbital of nitrogen and atomic size of $\ce{P > N}$ so $\ce{IP}$ is $N > P$.
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MCQ 1101 Mark
Who developed the long form of the periodic table?
  • Niels Bohr.
  • B
    Moseley.
  • C
    Mendeleef.
  • D
    Lothar Meyer.
Answer
Correct option: A.
Niels Bohr.
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MCQ 1111 Mark
The property which regularly increases down the group in the periodic table is :
  • A
    Ionisation energy
  • B
    Electronegativity
  • Reducing nature
  • D
    Electron affinity
Answer
Correct option: C.
Reducing nature
The metallic character is used to define the chemical property that metallic elements present. Generally, metals tend to lose electrons to form cations. Nonmetals tend to gain electrons to form anions.
They also have a high oxidation potential therefore they are easily oxidized and are strong reducng agents.
Thus the property which regularly increases down the group in the periodic table is Reducing nature.
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MCQ 1121 Mark
Number of short periods in Mendeleev's periodic table is :
  • A
    $2$
  • $3$
  • C
    $4$
  • D
    $1$
Answer
Correct option: B.
$3$
Period number $1, 2$ and $3$ contain $2, 8$ and $8$ elements respectively. Other periods contain more than $8$ elements.
Hence, the first three periods are called as short periods. So, total of $3$ short periods are there in Mendeleev periodic table.
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MCQ 1131 Mark
Which of the following radii reflect an increase in size of an atom?
  • Van der Waals' radius.
  • B
    Metallic radius.
  • C
    Covalent $($non $-$ metallic$)$ radius.
  • D
    Both $(b)$ and $(c).$
Answer
Correct option: A.
Van der Waals' radius.
The size of the atom increases as reflected in the van der Waals' radius.
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MCQ 1141 Mark
Choose the correct order of atomic radii of fluorine and neon $($in $\ce{pm})$ out of the options given below and justify your answer.
  • $72, 160$
  • B
    $160, 160$
  • C
    $72, 72$
  • D
    $160, 72$
Answer
Correct option: A.
$72, 160$
Atomic radius decreases as we move from left to right in a period in the periodic table. Fluorine has the smallest atomic radius. As we move to neon in the same period, the atomic radius increases as it has van der Waals radius and van der Waals radii are bigger than covalent radii.
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MCQ 1151 Mark
ns$^1$ and ns$^2$ outermost electronic configuration of s-block elements. They are all reactive metals with:
  • A
    High ionisation enthalpies.
  • Low ionisation enthalpies.
  • C
    Larger principal quantum number.
  • D
    None of the above.
Answer
Correct option: B.
Low ionisation enthalpies.
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MCQ 1161 Mark
Which one of the following is correct order of electron gain enthalpy?
  • A
    $\ce{S < O < Cl < F}$
  • B
    $\ce{Cl < F < S < O}$
  • C
    $\ce{F < Cl < O < S}$
  • $\ce{O < S < F < Cl}$
Answer
Correct option: D.
$\ce{O < S < F < Cl}$
Oxygen and fluorine has exceptionally small size, therefore more interelectronic repulsion that is why have lower electron gain enthalpy than $\ce{S}$ and $\ce{Cl}$ respectively.
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MCQ 1171 Mark
The incorrect statement among the following is :
  • A
    The first ionisation potential of $\ce{Al}$ is less than the first ionisation potential of $\ce{Mg}$.
  • The second ionisation potential of $\ce{Mg}$ is greater than the second ionisation potential of $\ce{N}.$
  • C
    The first ionisation potential of $\ce{Na}$ is less than the first ionisation potential of $\ce{Mg}.$
  • D
    The third ionisation of potential of $\ce{Mg}$ is greatest.
Answer
Correct option: B.
The second ionisation potential of $\ce{Mg}$ is greater than the second ionisation potential of $\ce{N}.$
After removal of an electron sodium acquires stable noble gas configuration. It is difficult to remove electron from stable noble gas configuration species.
Therefore, second ionization potential of $\ce{Mg}$ is less than that of $\ce{Na}$.
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MCQ 1181 Mark
In Mendeleev table, the triad of $\ce{VIII}$ group is :
  • $\ce{Ru, Rh, Pd}$
  • B
    $\ce{Cu, Ag, Au}$
  • C
    $\ce{N, O, F}$
  • D
    $\ce{Tl, Pb, Bi}$
Answer
Correct option: A.
$\ce{Ru, Rh, Pd}$
Group $\ce{VIII}$ of Mendeleev's table consists of three triads known as transition triads and they are :
Iron, Cobalt, and Nickel.
Ruthenium, Rhodium, and Palladium.
Osmium, Iridium, and Platinium.
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MCQ 1191 Mark
Which is not correct in case of $\ce{Be}$ and $\ce{Al}\ ?$
  • A
    Both are rendered passive by conc. $\ce{HNO_3}$.
  • B
    Carbides of both give methane on hydrolysis.
  • Both give hydroxides which are basic.
  • D
    Both give covalent chlorides.
Answer
Correct option: C.
Both give hydroxides which are basic.
Both form amphoteric hydroxide/oxide not either basic or acidic.
Because as Aluminium is in $3^{rd}$ group it can either accept electron or donate hence they form oxides which are amphoteric.
The reason why beryllium forms is aluminium and beryllium has diagonal relationship.
Hence both will have common properties.
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MCQ 1201 Mark
The term atomic radius refers to?
  • A
    Charge of the atom
  • Size of the atom
  • C
    Distance between the centre of nucleus and the first shell.
  • D
    Size of the outermost orbital.
Answer
Correct option: B.
Size of the atom
The atomic radius refers to the size of an atom.
It is the distance between the centre of the nucleus and the outermost shell of an atom.
Atomic radius generally decreases on moving left to right across a period and increases down the group.
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MCQ 1211 Mark
The polarizing power of the following anions $\ce{N^{3-}, O^{2-}}$ and $\ce{F}^-$, follow the order.
  • A
    $\mathrm{N}^{3-}<\mathrm{F}^{-}<\mathrm{O}^{2-} $
  • B
    $ \mathrm{O}^{2-}<\mathrm{N}^{3-}<\mathrm{F}^{-} $
  • C
    $\mathrm{O}^{2-}<\mathrm{F}^{-}<\mathrm{N}^{3-} $
  • $ \mathrm{N}^{3-}>\mathrm{O}^{2-}>\mathrm{F}^{-} $
Answer
Correct option: D.
$ \mathrm{N}^{3-}>\mathrm{O}^{2-}>\mathrm{F}^{-} $
Larger the anion, more will be the polarizing power.
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MCQ 1221 Mark
The element with positive electron gain enthalpy is :
  • A
    Hydrogen.
  • B
    Sodium.
  • C
    Oxygen.
  • Neon.
Answer
Correct option: D.
Neon.
It has positive electron enthalpy due to stable electron gain enthalpy, there is repulsion between electron to be added and valence electrons.
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MCQ 1231 Mark
$\ce{IE}$ of an element does not depend on :
  • A
    Its nuclear charge
  • B
    The shielding effect
  • Electron neutrality
  • D
    Penetration effect
Answer
Correct option: C.
Electron neutrality
Factors affecting ionisation potential,
Atomic size : Larger the atomic size, smaller is the Ionisation Potential. It is due to that the size of atom increases the outermost electrons farther away from the nucleus and nucleus loses the attraction on that electrons and hence can be easily removed.
Effective nuclear charge $(\ce{Z_{eff}})$ : Ionisation potential increases with the increase in nuclear charge between outermost electrons and nucleus.
Screening effect : Higher is the screening effect on the outer electrons causes less attraction from the nucleus and can be easily removed, which is leading to the lower value of Ionisation potential.
Penetration power of subshells and stability of half-filled and fully filled orbitals.
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MCQ 1241 Mark
Alkaline earth $($group $2$ or $\ce{IIA}$ elements) differ from group $12 \ ($or $\ce{IIB})$ elements in the electronic configuration of their :
  • A
    Anitipenultimate shell
  • B
    Innermost shell
  • C
    Outermost shell
  • Penultimate shell
Answer
Correct option: D.
Penultimate shell
Electronic configuration Alkaline earth $($group $2$ or $\ce{IIA}$ elements$)$ is $\ce{ns}^2$
Electronic configuration group $12\ ($or $\text{IIB})$ elements is $\ce{ns^2,(n−1)d^{10}}$,
so these twogroups differ in their electronic configaration of penultimate shell.
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MCQ 1251 Mark
Ionization energy is highest in $ .........$
  • A
    $\ce{[Ne]3s^1}$
  • $\ce{[Ne]3s^23p^3}$
  • C
    $\ce{[Ne]3d^{10}4s^24p^3}$
  • D
    $\ce{[Ne]3s^23p^4}$
Answer
Correct option: B.
$\ce{[Ne]3s^23p^3}$
$\ce{[Ne]3s^23p^3}$ has the highest ionisation energy because along the period ionisation energy increases $($as effective nuclear charge increases$).$
It has a half $-$ filled $3p$ sublevel which is more stable than a partially filled sublevel in $\ce{[Ne]3s^23p^4}$, sulphur. This is why phosphorus has higher first ionization energy than sulphur.
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MCQ 1261 Mark
The first ionisation enthalpies of $\ce{Na, Mg, Al}$ and $\ce{Si}$ are in the order :
  • $\ce{Na < mg > Al < Si}$
  • B
    $\ce{Na > mg > Al > Si}$
  • C
    $\ce{Na < Mg < Al < Si}$
  • D
    $\ce{Na > mg > Al < Si}$
Answer
Correct option: A.
$\ce{Na < mg > Al < Si}$
The electronic configurations are as follows :
${_1}1\text{Na}(3\text{s})^1,\ {_1}2\text{Mg(3s)}^2,\ {_1}3\text{AI(3s)}^2(3\text{p})^1,\ {_1}4\text{Si}(3\text{s})^2(3\text{p})^2$
The ionization energy of $\ce{Mg}$ will be larger than that of $\ce{Na}$ due to fully filled configuration $(3s)^2$
The ionization of $\ce{Al}$ will be smaller than that of $\ce{Mg}$ due to one electron extra than the stable configuration but smaller than $\ce{Si}$ due to increase in effective nuclear charge of $\ce{Si}.$
$\Rightarrow \ce{Na < Mg > Al < Si}$
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MCQ 1271 Mark
Correct order of $1^{st} \ \ce{ IP}$ among following elements $\ce{Be, B, C, N, O}$ is :
  • A
    $\ce{B < Be < C < O < N}$
  • $\ce{B < Be < C < N < O}$
  • C
    $\ce{Be < B < C < N < O}$
  • D
    $\ce{Be < B < C < O < N}$
Answer
Correct option: B.
$\ce{B < Be < C < N < O}$
The $1^{st}$ Ionisation Potential increases across a period as atomic size decreases. 
Given elements are $\ce{Be,B, C, N, O}.$
$1^{st}$ Ionisation Potential order is $\ce{B < Be < C < N < O}.$
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MCQ 1281 Mark
The ions with the positive charge or negative charge will have the radius, respectively :
  • Smaller or greater.
  • B
    Greater or smaller.
  • C
    Remains same.
  • D
    None of these.
Answer
Correct option: A.
Smaller or greater.
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MCQ 1291 Mark
The electronic configuration of gadolinium $($Atomic number $64)$
  • A
    $\big[\text{Xe}\big]\ 4\text{f}^3\ 5\text{d}^5\ 6\text{s}^2 $
  • B
    $\big[\text{Xe}\big]\ 4\text{f}^7\ 5\text{d}^2\ 6\text{s}^1$
  • $\big[\text{Xe}\big]\ 4\text{f}^7\ 5\text{d}^1\ 6\text{s}^2$
  • D
    $\big[\text{Xe}\big]\ 4\text{f}^8\ 5\text{d}^6\ 6\text{s}^2$
Answer
Correct option: C.
$\big[\text{Xe}\big]\ 4\text{f}^7\ 5\text{d}^1\ 6\text{s}^2$
The electronic configuration of $\ce{La (Z = 57)}$ is $\ce{[Xe] 5dl 6s}^2$. Therefore, further addition of electrons occurs in the lower energy $\ce{4f}-$ orbital till it is exactly half $-$ filled at $\ce{Eu (Z = 63)}$ Thus, the electronic configuration of $\ce{Eu}$ is $\ce{[Xe] 4f^7 6s}^2$. Thereafter, addition of next electron does not occur in the more stable exactly half $-$ filled $4f^7$ shell but occurs in the little higher energy $5d-$ orbital. Thus, the electronic configuration of $\ce{Gd (Z = 64)}$ is $\big[\text{Xe}\big]\ 4\text{f}^7\ 5\text{d}^1\ 6\text{s}^2$
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MCQ 1301 Mark
Which of the following elements has the highest ionization energy?
  • A
    $\ce{Al}$
  • B
    $\ce{In}$
  • C
    $\ce{Ga}$
  • $\ce{B}$
Answer
Correct option: D.
$\ce{B}$
In the fifth group, ionization potential $\ce{(I.E)}$ decreases on moving down the group from top to bottom.
Therefore, boron $\ce{(B)}$ has the highest $\ce{I.E}.$
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MCQ 1311 Mark
A solution of $\ce{CuSO_4}$ was kept in an iron pot. After few days the iron pot was found to have a number of holes in it. The balance equation of the reaction involve is :
  • A
    $\ce{2Fe + CuSO_4​ \rightarrow Fe_2(SO_4)_3 + Cu}$
  • $\ce{Fe + CuSO_4 \rightarrow FeSO_4​ + Cu}$
  • C
    $\ce{3Fe + CuSO_4 \rightarrow Fe_3 (SO_4​)_4​ + Cu}$
  • D
    $\ce{Fe + CuSO_4 \rightarrow Fe_2 SO_4 + Cu}$
Answer
Correct option: B.
$\ce{Fe + CuSO_4 \rightarrow FeSO_4​ + Cu}$
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MCQ 1321 Mark
Which among the following sets of groups consist elements with high chemical reactivity?
  • A
    Groups $-1$ and $11$
  • B
    Groups $-11$ and $17$
  • Groups $-1$ and $17$
  • D
    Groups $-11$ and $18$
Answer
Correct option: C.
Groups $-1$ and $17$
Groups $-1$ and $17$ consist highly reactive elements.
They tend to lose and gain electron $(s)$ respectively to achieve inert gas configuration.
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MCQ 1331 Mark
An element is placed in the $2^{nd}$ group and $3^{rd}$ period of the periodic table, burns in presence of oxygen to form a basic oxide. The electronic configuration of the element is $ ..........$
  • A
    $\ce{K, M, L (2, 8, 2)}$
  • B
    $\ce{K, L, M (2, 6, 4)}$
  • C
    $\ce{K, M, L (4, 6, 2)}$
  • $\ce{K, L, M (2, 8, 2)}$
Answer
Correct option: D.
$\ce{K, L, M (2, 8, 2)}$
As it is in $3^{rd}$ period, it has $3$ shells and since it is in the second group, it contains $2$ valence electrons.
Thus, the electronic configuration will be $2,8,2.$
Hence, it has $12$ electrons, that is, magnesium.
$\ce{2Mg + O2​ \rightarrow 2MgO}.$
It satisfies given condition which is a basic oxide.
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MCQ 1341 Mark
Which is the metallic element?
  • $Y$
  • B
    $X$
  • C
    Both $A$ and $B$
  • D
    None of the above
Answer
Correct option: A.
$Y$
$Y : 2, 8, 2$ is a metallic element as it has a tendency to loose an electron and get stable octet configuration.
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MCQ 1351 Mark
The alkaline earth metal which shows properties similar to aluminium is :
  • A
    $\ce{Ca}$
  • $\ce{Be}$
  • C
    $\ce{Sr}$
  • D
    $\ce{Ba}$
Answer
Correct option: B.
$\ce{Be}$
Beryllium and aluminum shows diagonal relationship with each other.
Hence, they exhibit similar properties.
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MCQ 1361 Mark
Fluorine is the most reactive among all the halogens, because of its :
  • A
    Small size
  • Low dissociation energy of $F - F$ bond.
  • C
    Large size
  • D
    High dissociation energy of $F - F$ bond.
Answer
Correct option: B.
Low dissociation energy of $F - F$ bond.
Fluorine is the most reactive among all the halogens, because of it's low dissociation energy of $F – F$ bond. The dissociation energies $\ce{(kcal/mol)}$ in $\ce{F_2​, Cl_2​, Br_2}$​ and $\ce{I_2}$​ are $38, 57, 45.5$ and $35.6$ respectively.
In the case of fluorine :
Short bond length and larger repulsion between non $-$ bonding electrons lead to low dissociation energy.
Absence of multiple bonding leads to low dissociation energy.
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MCQ 1371 Mark
The electronic configuration of silicon is $ ......... $ and that of sulphur is $ .........$
  • A
    Silicon $- 2, 8, 1$ ; Sulphur $- 2, 8, 6$
  • B
    Silicon $- 2, 8, 4$ ; Sulphur $- 2, 8, 3$
  • C
    Silicon $- 2, 8, 2$ ; Sulphur $- 2, 8, 6$
  • Silicon $- 2, 8, 4$ ; Sulphur $- 2, 8, 6$
Answer
Correct option: D.
Silicon $- 2, 8, 4$ ; Sulphur $- 2, 8, 6$
Atomic no. of $\ce{Si}$ is $14$ the electronic configuration : $2, 8, 4$
Atomic no. of $S$ is $16$ the electronic configuration : $2, 8, 6$
First shell has $2$ electrons. second shell can have a maximum of $8$ electrons. the next shell can hold a maximum of $8$ electrons as well.
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MCQ 1381 Mark
Electronic configuration of sodium is :
  • A
    $(2, 8, 1)$
  • B
    $(2, 8, 2)$
  • C
    $(2, 8, 3 )$
  • $(2, 8, 4)$
Answer
Correct option: D.
$(2, 8, 4)$
Atomic no. of $\ce{Na}$ is $11$ thus the $\ce{E.C}$ is : $2, 8, 1$
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MCQ 1391 Mark
The set representing the correct order of first ionisation potential is :
  • A
    $\ce{K > Na > Li}$
  • $\ce{Be > Mg > Ca}$
  • C
    $\ce{B > C > N}$
  • D
    $\ce{Ge > Si > C}$
Answer
Correct option: B.
$\ce{Be > Mg > Ca}$
Size increases as we move down the group.
Therefore, the outer electrons experience less attraction due to increase in distance,
i.e., the effective nuclear charge experienced is less. Less the effective nuclear charge less the $\ce{I.P}.$
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MCQ 1401 Mark
Compare the properties of metals and non $-$ metals with respect to electronic configuration.
  • A
    Metals have $1, 2$ valence electrons while non metals have $3, 5, 6$ or $7$ valence electrons.
  • B
    Metals have $1$ or $3$ valence electrons while non metals have $2, 5$ valence electrons.
  • C
    Metals have $2$ or $3$ valence electrons while non metals have $1, 5, 6$ or $7$ valence electrons.
  • Metals have $1, 2$ or $3$ valence electrons while non metals have $4, 5, 6$ or $7$ valence electrons.
Answer
Correct option: D.
Metals have $1, 2$ or $3$ valence electrons while non metals have $4, 5, 6$ or $7$ valence electrons.
Metals have $1, 2$ or $3$ valence electron while non metals have $4, 5, 6$ or $7$ valence electron
${< \ce{image}}$ compare the properties of metals and non $-$ metals with respect to electronic configuration.
 
 
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MCQ 1411 Mark
Boron is diagonally related to :
  • A
    Boron
  • B
    Aluminium
  • C
    Magnesium
  • Silicon
Answer
Correct option: D.
Silicon
Boron and silicon are both semiconductors, form halides that are hydrolysed in water and form acidic oxides. Boron and silicon have diagonal relationship.
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MCQ 1421 Mark
Which of the following elements require least energy for excitation?
  • A
    Flourine
  • B
    Chlorine
  • C
    Bromine
  • Iodine
Answer
Correct option: D.
Iodine
The outer electrons of iodine do not experience much attraction towards the nucleus due to the shielding effect. Therefore, iodine requires the least energy for excitation $($due to the large distance of valence electrons from the nucleus$).$
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MCQ 1431 Mark
Among halogens, the correct order of amount of energy released in electron gain $($electron gain enthalpy$)$ is :
  • A
    $\ce{F > Cl > Br > I}$
  • B
    $\ce{F < Cl < Br < I}$
  • $\ce{F < Cl > Br > I}$
  • D
    $\ce{F < Cl < Br < I}$
Answer
Correct option: C.
$\ce{F < Cl > Br > I}$
Within a group, electron gain enthaply becomes less negative down a group.
However, adding an electron to the $2p\ -$ orbital leads to greater repulsion than adding an electron to the larger $3p\ -$ orvital.
Hence, the element with most negative electron gain enthalpy is chlorine.
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MCQ 1441 Mark
What effect is observed, on the size of an atom when an electron is removed and in another case an electron is added to the same atom?
  • A
    Size increases and decreases respectively.
  • Size decreases and increases respectively.
  • C
    Size increases in both cases.
  • D
    Size decreases in both cases.
Answer
Correct option: B.
Size decreases and increases respectively.
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MCQ 1451 Mark
The numerical value of ionization energy of a unipositive ion is approximately equal to $ ..........$
  • A
    $\ce{IP}$ value of neutral atom.
  • B
    $\ce{EA}$ value of neutral atom.
  • C
    $\ce{IP}$ value of dipositive ion.
  • $\ce{EA}$ value of dipositive ion.
Answer
Correct option: D.
$\ce{EA}$ value of dipositive ion.
Ionization energy of unipositive ion means removing electron from unipositive ion.
$\ce{X^+ −e^- \rightarrow X}^{++}$
And electron affinity means electron added to dipositive ion.
$\ce{X^{++} +e^- \rightarrow X}^+$
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MCQ 1461 Mark
The type of elements present in group $18[0]$ are :
  • A
    Alkali metals
  • B
    Alkaline earth metals
  • C
    Halogens
  • Noble gases
Answer
Correct option: D.
Noble gases
Group $18$ elements have complete octet except He and they are inert in nature so this group represents noble gases/inert gases.
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MCQ 1471 Mark
$\ce{IP}$ is influenced by :
  • A
    Size of atom
  • B
    Effective nuclear charge.
  • C
    Electrons present in inner shell.
  • All
Answer
Correct option: D.
All
$\ce{IP}$ is influenced by:
size of atom : Higher is the size of the atom, lower will be its ionization potential.
Effective nuclear charge : Higher is the effective nuclear charge, higher will be its ionisation potential.
Electrons present in inner shell : When more electrons are present in inner shells, higher is the screening effect and lower is the effective nuclear charge.
Hence, lower will be the ionization potential.
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MCQ 1481 Mark
$\ce{I.P}$. of sodium is $\ce{5.14 eV}$ then $\ce{I.P.}$ of potassium will be :
  • A
    Equal to sodium
  • B
    $\ce{5.68 eV}$
  • $\ce{4.34 eV}$
  • D
    $\ce{10.28 eV}$
Answer
Correct option: C.
$\ce{4.34 eV}$
$\ce{I.P}$. of sodium is $\ce{5.14 eV}$ then $\ce{I.P}$. of potassium will be $\ce{4.34 eV}$. On moving down a group, the ionization potential decreases.
Hence, the ionization potential of potassium should be lower than the ionization potential of sodium.
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MCQ 1491 Mark
Which of the following is not an actinoid?
  • A
    Curium $\ce{(Z = 96)}$
  • B
    Californium $\ce{(Z = 98)}$
  • C
    Uranium $\ce{(Z = 92)}$
  • Terbium $\ce{(Z = 65)}$
Answer
Correct option: D.
Terbium $\ce{(Z = 65)}$
Actinoids are elements with $\ce{Z= 90 - 103}$.
Therefore, Terbium $\ce{(Z = 65)}$ is not an actinoid.
Terbium $\ce{(Z = 65)}$ is a lanthanoid. $\text{Tb:}\ [\text{xe}]4\text{f}^95\text{d}^06\text{s}^2$
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MCQ 1501 Mark
Electronic configuration $\ce{1 s^2 2 s^2 2 p x^1 2 p y^1 2 p z^1}$ corresponds to :
  • $\ce{N}$
  • B
    $\ce{Cr}$
  • C
    $\ce{O}$
  • D
    $\ce{F}$
Answer
Correct option: A.
$\ce{N}$
Total number of electrons $= 7.$
Therefore, atomic number of the element is $7,$ which is the atomic number of $N$.
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MCQ 1511 Mark
The outermost electronic configuration of $p-$ block elements varies from ${n s^2 n p^1}$ to :
  • A
    ${n s^2 n p^5} $
  • B
    ${ n s^2 n p^4} $
  • ${n s^2 n p^6}$
  • D
    ${n s^2 n p^3}$
Answer
Correct option: C.
${n s^2 n p^6}$
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MCQ 1521 Mark
The oxide formed by the element on extreme right and in the left of periodic table are generally :
  • A
    Acidic, amphoteric respectively.
  • Acidic, basic respectively.
  • C
    Neutral, amphoteric respectively.
  • D
    Basic, neutral respectively.
Answer
Correct option: B.
Acidic, basic respectively.
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MCQ 1531 Mark
Which of the following decreases in going down the halogen group?
  • A
    Ionic radius
  • B
    Atomic radius
  • Ionisation potential
  • D
    Boiling point
Answer
Correct option: C.
Ionisation potential
On moving down the halogen group, the atomic radius, ionic radius and the boiling point increases with an increase in the atomic number. However, ionisation potential decreases. The effect of an increase in the atomic size and the shielding effect is much more than the effect of the increase in nuclear charge.
Hence, the electron becomes less and less firmly held to the nucleus on moving down the group. Hence, the ionization potential gradually decreases on moving down the group.
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MCQ 1541 Mark
Which of the following compounds is/ are amphoteric in nature?
  • A
    $\ce{{Cl}_2 {O}_7}$
  • B
    $\ce{{Al}_2 {O}_3}$
  • C
    $\ce{{As}_2 {O}_3}$
  • Both $(b)$ and $(c).$
Answer
Correct option: D.
Both $(b)$ and $(c).$
$\ce{{Al}_2 {O}_3}$ and $\ce{{As}_2 {O}_3}$ are amphoteric in nature.
Amphoteric oxides behave as acidic with bases and basic with acids.
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MCQ 1551 Mark
Mendeleev classified elements in :
  • A
    Increasing order of atomic groups.
  • Seven periods and eight groups.
  • C
    Seven periods and nine groups
  • D
    Eight periods and seven groups.
Answer
Correct option: B.
Seven periods and eight groups.
Mendeleev kept elements in increasing order of atomic weights in seven periods and eight groups.
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MCQ 1561 Mark
The non $-$ radio active metal of $\ce{IIA}$ group having least first ionisation potential is :
  • A
    Radium
  • B
    Beryllium
  • C
    Calcium
  • Barium
Answer
Correct option: D.
Barium
On moving down the group of alkaline earth metals, the atomic size of metals increases and their first ionization enthalpies decreases from $\ce{Be}$ to $\ce{Ba}$. Thus non radioactive barium has least first ionization enthalpy among the non radioactive elements of group $\ce{IIA}.$
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MCQ 1571 Mark
The highest first ionisation energy among the following elements.
  • A
    $\ce{Cs}$
  • $\ce{Cl}$
  • C
    $\ce{I}$
  • D
    $\ce{Li}$
Answer
Correct option: B.
$\ce{Cl}$
The first ionisation energy of nonmetals is very high and as we move down the group, it decreases so $\ce{Cl}$ have highest first ionisation energy among all.
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MCQ 1581 Mark
The formation of the oxide ion, $ O^{2-} (g),$ from oxygen atom requires first an exothermic and then an endothermic step as shown below: $\text{O(g)}+\text{e}^-\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }\text{O}^-(\text{g}),\ \Delta\text{H}^\ominus=-141\ \text{kJ}\text{ mol}^{-1}$ $\text{O(g)}+\text{e}^-\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }\text{O}^{-2}(\text{g}),\ \Delta\text{H}^\ominus=+780\ \text{kJ}\text{ mol}^{-1}$ Thus process of formation of $O^{2-}$ in gas phase is unfavourable even though $O^{2-}$ is isoelectronic with neon. It is due to the fact that:
  • A
    Oxygen is more electronegative.
  • B
    Addition of electron in oxygen results in larger size of the ion.
  • Electron repulsion outweighs the stability gained by achieving noble gas configuration.
  • D
    $O^-$ ion has comparatively smaller size than oxygen atom.
Answer
Correct option: C.
Electron repulsion outweighs the stability gained by achieving noble gas configuration.
$O^-$ ion will tend to resist the addition of another electron.
$\text{O}^-(\text{g})+\text{e}^-\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }\text{O}^{-2}(\text{g}),\ \Delta\text{H}^0-844\ \text{kJ}\text{ mol}^{-1}$
This process is unfavorable in the gas phase because the resulting increase in electron$-$electron repulsion overweight’s the stability gained by achieving the noble gas configuration.
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MCQ 1591 Mark
According to $\ce{IUPAC},$ total number of groups and periods in the periodic table respectively are :
  • A
    $16, 9$
  • $18, 7$
  • C
    $18, 9$
  • D
    $13, 7$
Answer
Correct option: B.
$18, 7$
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MCQ 1601 Mark
Which of the following requires highest energy?
  • A
    $\ce{M(g) \rightarrow M^+(g)}$
  • B
    $\ce{M(g) \rightarrow M^{2+}(g)}$
  • C
    $\ce{M(g) \rightarrow M^{3+}(g)}$
  • $\ce{M(g) \rightarrow M^{4+}(g)}$
Answer
Correct option: D.
$\ce{M(g) \rightarrow M^{4+}(g)}$
This requires highest energy to lose four electrons.
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MCQ 1611 Mark
Atom with $ ......... $ atomic radii and $ ........ $ ionisation potential tends to gain electrons :
  • A
    Large, high
  • B
    Large, low
  • C
    Small, low
  • Small, high
Answer
Correct option: D.
Small, high
Ionization energies increase moving from left to right across a period $($decreasing atomic radius$).$
So, atom with small atomic radii and high ionisation potential tends to gain electrons.
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MCQ 1621 Mark
Identify the electronic configuration of an element whose atomic radii is determined by taking half the internuclear distance between like atoms.
  • $\ce{[He]2s^22p5}$
  • B
    $\ce{[Ar]4s^2}$
  • C
    $\ce{[Ne]3s^2}$
  • D
    $\ce{[Kr]4d^55s^2}$
Answer
Correct option: A.
$\ce{[He]2s^22p5}$
The atomic radii of non $-$ metallic elements are determined by taking half the internuclear distance between like atoms.
The only non $-$ metal in the given options is option $A,$ which is Flourine.
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MCQ 1631 Mark
Mendeleev's left the gap nder aluminium and a gap under silicon having atomic weights $68$ and $72$ respectively. These elements respectively are :
  • Eka $-$ aluminium and Eka $-$ silicon.
  • B
    Aluminium and silicon.
  • C
    Eka $-$ germanium and Eka $-$ silicon.
  • D
    Eka $-$ aluminium and Eka $-$ germanium.
Answer
Correct option: A.
Eka $-$ aluminium and Eka $-$ silicon.
Mendeleev left the gap under aluminium and a gap under silicon, are called as Eka $-$ aluminium and Eka $-$ silicon, respectively.
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MCQ 1641 Mark
Among the following four elements, the ionisation potential of which one is the highest?
  • A
    Oxygen
  • Argon
  • C
    Barium
  • D
    Caesium
Answer
Correct option: B.
Argon
Noble gases have very stable configuration. It is not easy to remove an electron from such a stable configuration. Thus, noble gases have the highest ionization potential in a particular group.
Therefore, among the given options argon has the highest ionization potential.
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MCQ 1651 Mark
Which of the following pairs show reverse properties on moving along a period from left to right and from top to bottom in a group?
  • Atomic radius and electron gain enthalpy $($negative value$).$
  • B
    Nuclear charge and ionisation enthalpy.
  • C
    Ionisation enthalpy and electron gain enthalpy $($negative value$).$
  • D
    None of the above.
Answer
Correct option: A.
Atomic radius and electron gain enthalpy $($negative value$).$
Atomic radius decreases from left to right in a period and increases from top to bottom in a group.
Similarly, the negative value of electron gain enthalpy decreases in a period and increases in a group.
So Atomic radius and electron gain enthalpy show reverse properties on moving along a period from left to right and in the group from top to bottom.
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MCQ 1661 Mark
An element belongs to $3^{rd}$ period and group $-13$ of the periodic table. Which of the following properties will be shown by the element?
  • Good conductor of electricity.
  • B
    Liquid, metallic.
  • C
    Solid, non metallic.
  • D
    Liquid, non metallic.
Answer
Correct option: A.
Good conductor of electricity.
Group $-\ 13$ third period element is Aluminum which is a metal. It is solid metallic and a good conductor of electricity.
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MCQ 1671 Mark
The outer electronic configuration of radioactive element present in $\ce{IA}$ group is :
  • A
    $\ce{8s^1}$
  • $\ce{7s^1}$
  • C
    $\ce{5s^1}$
  • D
    $\ce{6s^1}$
Answer
Correct option: B.
$\ce{7s^1}$
The radioactive element in group $1A$ is francium $\ce{(Fr)}$ atomic number $87$ having electronic configuration $\ce{(Rn) 7s^1}$.
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MCQ 1681 Mark
The electronegativities of $\ce{C, N, Si}$ and Pare in order of :
  • $\ce{Si < P < C < N}$
  • B
    $\ce{Si < P < N < C}$
  • C
    $\ce{P < Si < N < C}$
  • D
    $\ce{P < Si < C < N}$
Answer
Correct option: A.
$\ce{Si < P < C < N}$
$\ce{Si}$ is largest in size, $'N\ '$ is smallest in size.
As the atomic size decreases, electronegativity increases.
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MCQ 1691 Mark
Periodic classification of elements can be done on the basis of electronic configuration and is used to examine the :
  • A
    Periodic trends in physical properties of elements.
  • B
    Periodic trends in chemical properties of elements.
  • Both $(a)$ and $(b).$
  • D
    None of the above.
Answer
Correct option: C.
Both $(a)$ and $(b).$
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MCQ 1701 Mark
Compound of a metal $′M\ ′$ is $\ce{M_2​O_3}$​. The formula of its nitride will be $-$
  • A
    $\ce{M_3​N}$
  • $\ce{MN}$
  • C
    $\ce{M_3​N_2}$
  • D
    $\ce{M_2​N_3}$
Answer
Correct option: B.
$\ce{MN}$
Compound of a metal $M$ formed $\ce{M_2​O_3}$ . It represent that $M$ have $3$ valency electrons.
So the nitride formed will be $\ce{MN}$.
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