Question
Identify the metal and justify your answer.
  1. Carbonyl $\ce{M (CO)_5}$
  2. $\ce{MO_3F}$

Answer

It is $= 0 x = +7M$ is in $+7$ oxidation state so that the given compound is $\ce{MnO_3F}$
  1. $\ce{Fe(CO)_5} $ by $\text{EAN}$ rule
$\text{EAN} = x + 2 \times 5 = 36 \ (Kr$ is the nearest inert gas$)$
$x = 26 ($atomic no. of the metal$)$ so the metal is iron.
  1. $\ce{MO_3F}$ is $\ce{MnO_3F}$
In $\ce{MO_3F}$ let us assume $M = x$
$x + 3 \times (-2) + (-1)$
$x = +7$
$M$ is in $+ 7$ osidation state so that the given compound is $\ce{MnO_3F}$

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