
- A

- B

- C

- D






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(Given: specific rotations of ($+$)-sucrose, ($+$)-maltose, $L$-($-$)-glucose anc. $+(+)$-fructose in aqueous solution are $+66^{\circ},+140^{\circ},-52^{\circ}$ and $+92^{\circ}$, respectively)
($A$) 'invert sugar' is prepared by acid catalyzed hydrolysis of maltose
($B$) . 'invert sugar' is an equimolar mixture of $D$-($+$)-glucose and $D$-($-$)-fructose
($C$) specific rotation of 'invert sugar' is $-20^{\circ}$
($D$) on reaction with $\mathrm{Br}_2$ water, 'invert sugar' forms saccharic acid as one of the products
$(a)\;\;60\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+40 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}$
$(b)\;\;55\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+45 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}$
$(c)\;\;75\; \mathrm{mL} \frac{\mathrm{M}}{5}\; \mathrm{HCl}+25 \;\mathrm{mL} \frac{\mathrm{M}}{5} \;\mathrm{NaOH}$
$(d)\;\;100\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+100 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}$
$pH$ of which one of them will be equal to $1$ ?

