MCQ
If $0.4\,gm\,\,NaOH$ is present in $ 1$ litre solution, then its $pH$ will be
- A$2$
- B$10$
- C$11$
- ✓$12$
✓
Answer
Correct option: D.
$12$
(d) $[NaOH] = \frac{{0.4}}{{40}} = 0.01\,M;\,\,\,\,\,[O{H^ - }] = {10^{ - 2}}\,M$
$[{H^ + }] = {10^{ - 12}},\,\,pH = - \log [{H^ + }] = 12$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Most unstable resonating structure of given is
Which of the following can act both as oxidizing and reducing agent ?
In which method oil bath is used?
No. of $\pi$ electrons in the following is :
→Determine the element if its ground state has $13$ electrons in its "$M-$ shell".
→The $pH$ of a solution is $2. $ If its $pH$ is to be raised to $ 4$, then the $[{H^ + }]$ of the original solution has to be
→$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_2} + HBr \to X(product)} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_{3\,\,\,\,\,\,\,\,\,\,\,}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
→{C{H_3} - CH - CH = C{H_2} + HBr \to X(product)} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_{3\,\,\,\,\,\,\,\,\,\,\,}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
What is the major product i.e. $X$ in the reaction?
Chlorine exists in two isotopic forms, $\text{Cl}-37$ and $\ce{Cl}-35$ but its atomic mass is $35.5$. This indicates the ratio of $\ce{Cl}-37$ and $\ce{Cl}-35$ is approximately :
→Calculate the wavelength (in nanometer) associated with a proton moving at $1.0 \times 10^3 ms^{-1}$ (Mass of proton $=$ $1.67 \times 10^{-27} kg$ and $h =6.63 \times 10^{-34} Js$ )
→At $25\,^o C$, the dissociation constant of a base $BOH$ is $1.0 \times {10^{ - 12}}$. The concentration of Hydroxyl ions in $0.01\, M$ aqueous solution of the base would be
→