MCQ
If $0.5\,amp$ current is passed through acidified silver nitrate solution for $10 $ minutes. The mass of silver deposited on cathode, is ........... $\mathrm{g}$ (eq. wt. of silver nitrate $= 108$)
- A$0.235$
- ✓$0.336$
- C$0.536$
- D$0.636$
✓
Answer
Correct option: B.
$0.336$
b
Weight of silver accumulated $W = ZIT$
Weight of silver accumulated $W = ZIT$
$W=(108 \times 0.5 \times 10 \times 60) /(96500)$
$W=0.33 \,g$
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