MCQ
If $0\,<\,x\,<\,1$, then $\frac{3}{2} x^{2}+\frac{5}{3} x^{3}+\frac{7}{4} x^{4}+\ldots . .$, is equal to :
  • $\mathrm{x}\left(\frac{1+\mathrm{x}}{1-\mathrm{x}}\right)-\log _{\mathrm{e}}(1-\mathrm{x})$
  • B
    $\mathrm{x}\left(\frac{1-\mathrm{x}}{1+\mathrm{x}}\right)+\log _{\mathrm{e}}(1-\mathrm{x})$
  • C
    $\frac{1-x}{1+x}+\log _{e}(1-x)$
  • D
    $\frac{1+x}{1-x}+\log _{e}(1-x)$

Answer

Correct option: A.
$\mathrm{x}\left(\frac{1+\mathrm{x}}{1-\mathrm{x}}\right)-\log _{\mathrm{e}}(1-\mathrm{x})$
a
Let $t=\frac{3}{2} x^{2}+\frac{5}{3} x^{3}+\frac{7}{4} x^{4}+\ldots . \infty$

$=\left(2-\frac{1}{2}\right) x^{2}+\left(2-\frac{1}{3}\right) x^{3}+\left(2-\frac{1}{4}\right) x^{4}+\ldots \infty$

$=2\left(\mathrm{x}^{2}+\mathrm{x}^{3}+\mathrm{x}^{4}+\ldots \infty\right)-\left(\frac{\mathrm{x}^{2}}{2}+\frac{\mathrm{x}^{3}}{3}+\frac{\mathrm{x}^{4}}{4}+\ldots \infty\right)$

$=\frac{2 x^{2}}{1-x}-(\ell n(1-x)-x)$

$\Rightarrow t=\frac{2 x^{2}}{1-x}+x-\ell n(1-x)$

$\Rightarrow t=\frac{x(1+x)}{1-x}-\ell n(1-x)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Two tangents are drawn from a point $P$ to the circle $x^{2}+y^{2}-2 x-4 y+4=0$, such that the angle between these tangents is $\tan ^{-1}\left(\frac{12}{5}\right)$, where $\tan ^{-1}\left(\frac{12}{5}\right) \in(0, \pi)$. If the centre of the circle is denoted by $C$ and these tangents touch the circle at points $A$ and $B$, then the ratio of the areas of $\Delta PAB$ and $\Delta CAB$ is :
If the roots of the equation $b{x^2} + cx + a = 0$ be imaginary, then for all real values of $x,$ the expression $3{b^2}{x^2} + 6bcx + 2{c^2} $ is :
The number of ordered pairs $(x, y)$ of positive integers satisfying $2^x+3^y=5^{x y}$ is
If the roots of equation $\frac{{{x^2} - bx}}{{ax - c}} = \frac{{m - 1}}{{m + 1}}$ are equal but opposite in sign, then the value of $m$ will be
Range of the function $f (x) =$ $\left[ {\frac{1}{{\ln ({x^2} + e)}}} \right]\,\, + \,\,\frac{1}{{\sqrt {1 + {x^2}} }}\,$  is , where $[*]$ denotes the greatest integer function and $e =$ $\mathop {Limit}\limits_{\alpha  \to 0} {(1 + \alpha )^{1/\alpha }}\,$
The length of the latus rectum of the parabola whose vertex is (2, -3) and the directrix x = 4 is:
Let $P_{1}$ be a parabola with vertex $(3,2)$ and focus $(4,4)$ and $P _{2}$ be its mirror image with respect to the line $x +2 y =6$. Then the directrix of $P _{2}$ is $x +2 y$ =
The equation of the circle with origin as centre passing the vertices of an equilateral triangle whose median is of length $3a$ is
Let the normals at all the points on a given curve pass through a fixed point $(a, b) .$ If the curve passes through $(3,-3)$ and $(4,-2 \sqrt{2}),$ and given that $a-2 \sqrt{2} b=3,$ then $\left(a^{2}+b^{2}+a b\right)$ is equal to ..... .
If $(\alpha ,\beta )$ is a point on the circle whose centre is on the $x -$ axis and which touches the line $x + y = 0$ at $(2, -2)$, then the greatest value of $\alpha$ is