MCQ
If $1\; g$ of steam is mixed with $1\; g$ of ice, then the resultant temperature of the mixture is ........ $^oC$
- ✓$100$
- B$50$
- C$230$
- D$270$
Heat gain $=1 \times 80+1 \times 1 \times(100-0)$
$=180 \mathrm{cal}$
Heat loss $=1 \times 540=540 \mathrm{cal}$
(means complete steam won't convert to water at $100^{\circ} \mathrm{C})$
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