MCQ
If $(1 + x - 3x^2)^{2145} = a_0 + a_1x + a_2x^2 + .........$ then $a_0 - a_1 + a_2 - a_3 + ..... $ ends with
  • A
    $1$
  • $3$
  • C
    $7$
  • D
    $9$

Answer

Correct option: B.
$3$
b
Put $x = - 1 ; (- 3)^{2145} = a_0 - a_1 + a_2 - a_3 + ...... ; - (3)^{2145}$

$ = - (3^4)^{536} · 3$ $\Rightarrow$ ends no. $3$ 

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