MCQ
If $(1 + x - 3x^2)^{2145} = a_0 + a_1x + a_2x^2 + .........$ then $a_0 - a_1 + a_2 - a_3 + ..... $ ends with
- A$1$
- ✓$3$
- C$7$
- D$9$
$ = - (3^4)^{536} · 3$ $\Rightarrow$ ends no. $3$
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