MCQ
If $10^x=64$,then $10^{\frac{x}{2}+1}$ is equal to
- A18
- B42
- ✓80
- D81
✓
Answer
Correct option: C.
80
(c)
We have,$10^x=64$
$\therefore \quad 10^{\frac{x}{2}+1}=10^{\frac{x}{2}} \times 10^1=\left(10^x\right)^{1 / 2} \times 10=64^{1 / 2} \times 10=\left(8^2\right)^{1 / 2} \times 10=8 \times 10=80$
We have,$10^x=64$
$\therefore \quad 10^{\frac{x}{2}+1}=10^{\frac{x}{2}} \times 10^1=\left(10^x\right)^{1 / 2} \times 10=64^{1 / 2} \times 10=\left(8^2\right)^{1 / 2} \times 10=8 \times 10=80$
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