If 19^ th terms of non -zero A.P. is zero, then its (49^ th term)… - Vidyadip

MCQ

If $19^{th}$ terms of non -zero $A.P.$ is zero, then its ($49^{th}$ term) : ($29^{th}$ term) is

A
$4 : 1$
B
$1 : 3$
✓
$3 : 1$
D
$2 : 1$

✓

Answer

Correct option: C.

$3 : 1$

c
$a + 18d = 0 \Rightarrow a = - 18d$

$\frac{{{t_{49}}}}{{{t_{29}}}} = \frac{{a + 48d}}{{a + 28d}} = \frac{{ - 18d + 48d}}{{ - 18d + 28d}}$

$ = \frac{{30d}}{{10d}} = 3$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from 8. sequence and series→8. sequence and series — all question types→MATHS STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The coefficent of $x^7$ in the expansion of ${\left( {1 - x - {x^2} + {x^3}} \right)^6}$ is

The length of the latus-rectum of the parabola $4y^2 + 2x - 20y + 17 = 0$ is

How many real tangents can be drawn to the ellipse $5x^2 + 9y^2 = 32$ from the point $(2,3)$

The negation of the statement: "If I become a teacher, then I will open a school" is:

A quadratic polynomial $ y = f (x)$ with absolute term $3$ neither touches nor intersects the abscissa axis and is symmetric about the line $x = 1$ . The coefficient of the leading term of the polynomial is unity. A point $A(x_1, y_1)$ with abscissa $x_1 = 1$ and a point $B(x_2, y_2) $ with ordinate $y_2 = 11 $ are given in a cartisian rectangular system of co-ordinates $OXY $ in the first quadrant on the curve $y = f (x)$ where $ 'O'$ is the origin. The scalar product of the vectors $\vec {OA}$ and $\vec {OB}$ is

The equation of a circle passing through the vertex and the extremities of the latus rectum of the parabola ${y^2} = 8x$ is

15 buses operate between Hyderabad and Tirupathi.The number of ways can a man go to Tirupathi from Hyderabad by a bus and return by a different bus is:

$\sum\limits_{n = 1}^n {{1 \over {{{\log }_{{2^n}}}(a)}}} = $

Let $A B C D$ be a square andlet $P$ be a point on segment $C D$ such that $D P: P C=1: 2$. Let $Q$ be a point on segment $A P$ such that $\angle B Q P=90^{\circ}$. Then, the ratio of the area of quadrilateral $P Q B C$ to the area of the square $A B C D$ is

Tangents are drawn to the circle $x^2 + y^2 = 1$ at the points where it is met by the circles, $x^2 + y^2 - (\lambda + 6) x + (8 - 2 \lambda ) y - 3 = 0 $ . $\lambda$ being the variable . The locus of the point of intersection of these tangents is :