MCQ
If $\frac{241}{4000}=\frac{241}{2^\text{m}\times5^\text{n}},$ Then :
- A$m = 4$ and $n = 5$
- B$m = 3$ and $n = 2$
- ✓$m = 5$ and $n = 3$
- D$m = 2$ and $n = 5$
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