MCQ
If $\frac{241}{4000}=\frac{241}{2^\text{m}\times5^\text{n}},$ Then :
  • A
    $m = 4$ and $n = 5$
  • B
    $m = 3$ and $n = 2$
  • $m = 5$ and $n = 3$
  • D
    $m = 2$ and $n = 5$

Answer

Correct option: C.
$m = 5$ and $n = 3$
$\frac{241}{4000}=\frac{241}{2^\text{m}\times5^\text{m}}$
$\Rightarrow\frac{241}{2^5\times5^3}=\frac{241}{2^\text{m}\times5^\text{n}}$
Comparing the denominators of both fractions, we have $m = 5$ and $n = 3$

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