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3 and 4 . determinant and metrices — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMaths3 and 4 . determinant and metrices1 Mark
MCQ
If $2X - \left[ {\begin{array}{*{20}{c}}1&2\\7&4\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}3&2\\0&{ - 2}\end{array}} \right]$, then $X$  is equal to
  • A
    $\left[ {\begin{array}{*{20}{c}}2&2\\7&4\end{array}} \right]$
  • B
    $\left[ {\begin{array}{*{20}{c}}1&2\\{7/2}&2\end{array}} \right]$
  • ✓
    $\left[ {\begin{array}{*{20}{c}}2&2\\{7/2}&1\end{array}} \right]$
  • D
    None of these
✓

Answer

Correct option: C.
$\left[ {\begin{array}{*{20}{c}}2&2\\{7/2}&1\end{array}} \right]$
c
(c) $2X - \left[ {\begin{array}{*{20}{c}}1&2\\7&4\end{array}} \right]\, = \,\left[ {\begin{array}{*{20}{c}}3&2\\0&{ - 2}\end{array}} \right]$

==> $2X = \left[ {\begin{array}{*{20}{c}}3&2\\0&{ - 2}\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}1&2\\7&4\end{array}} \right]$

==> $2X = \left[ {\begin{array}{*{20}{c}}4&4\\7&2\end{array}} \right]$ 

==> $X = \left[ {\begin{array}{*{20}{c}}2&2\\{7/2}&1\end{array}} \right]$.

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