If − 3x + 17 < -13, then: 1. x (10, ) 2. x [10, ) 3. x (- ,10] 4.… - Vidyadip

Question

If − 3x + 17 < -13, then:

$\text{x}\in(10,\infty)$
$\text{x}\in[10,\infty)$
$\text{x}\in(-\infty,10]$
$\text{x}\in[-10,10)$

✓

Answer

$\text{x}\in(10,\infty)$

Solution:

− 3x + 17 < −13

Subtracting 17 on both sides, we get

⇒ −3x + 17 − 17 < −13 − 17

⇒ −3x < − 30

Dividing −3 on both sides, we get

$\Rightarrow\frac{-3\text{x}}{-3}>\frac{-30}{-3}$

$\Rightarrow\text{x}>10$

$\Rightarrow\text{x}\in(10,\infty)$

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