If |x−1| x - 1 > 5, then:
View full solution →- $\text{x}\in(-4,6)$
- $\text{x}\in[-4,6]$
- $\text{x}\in(-\infty,-4)\cup(6,\infty)$
- $\text{x}\in(-\infty,-4)\cup[6,\infty)$