If – 3x + 17 < – 13, then: - Vidyadip

MCQ

If – 3x + 17 < – 13, then:

A
$\text{x}\in(10,\infty)$
B
$\text{x}\in\big[10,\infty)$
C
$\text{x}\in(-\infty,10\big]$
D
$\text{x}\in\big[-10,10)$

✓

Answer

$\text{x}\in(10,\infty)$

Solution:

Given,

-3x + 17 < -13

Subtracting 17 from both sides,

-3x + 17 – 17 < -13 – 17

$\Rightarrow$ -3x < -30

$\Rightarrow$ x > 10 (since the division by negative number inverts the inequality sign)

$\Rightarrow\text{x}\in(10,\infty)$

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