MCQ
If $4, x_1, x_2, x_3, 28$ are in $AP$ then $x_3= ?$
- A$19$
- B$23$
- ✓$22$
- DCannot be determined
✓
Answer
Correct option: C.
$22$
Given that $4,\text{x}_1,\text{x}_2,\text{x}_3,28$ are in $AP$.
Let $d$ be the common difference.
Since $28$ is the $5^{th}$ term,
$28 = 4 + 4d$
$\Rightarrow 4d = 24$
$\Rightarrow d = 6$
$x_3= a + (3)d .....$
$(x_3$ is the fourth term$)$
$\Rightarrow x_3= 4 + 3(6)$
$\Rightarrow x_3= 22$
Let $d$ be the common difference.
Since $28$ is the $5^{th}$ term,
$28 = 4 + 4d$
$\Rightarrow 4d = 24$
$\Rightarrow d = 6$
$x_3= a + (3)d .....$
$(x_3$ is the fourth term$)$
$\Rightarrow x_3= 4 + 3(6)$
$\Rightarrow x_3= 22$
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