Question
If $\frac{4}{5},\text{a},2$ are in AP, find the value of a.
✓
Answer
If $\frac{4}{5},\text{a}$ and 2 are three consecutive terms of an AP, then we have:
$\text{a}-\frac{4}{5}=2-\text{a}$
$\Rightarrow2\text{a}=2+\frac{4}{5}$
$\Rightarrow2\text{a}=\frac{14}{5}$
$\Rightarrow\text{a}=\frac{7}{5}$
$\text{a}-\frac{4}{5}=2-\text{a}$
$\Rightarrow2\text{a}=2+\frac{4}{5}$
$\Rightarrow2\text{a}=\frac{14}{5}$
$\Rightarrow\text{a}=\frac{7}{5}$
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