Question
Find the arithmetic mean of each of the following frequency distributions using step-deviation method:
Class
500-520
520-540
540-560
560-580
580-600
600-620
Frequency
14
9
5
4
3
5

Answer

Age
Frequency $f_i$
Mid-value $x_i$
$\text{u}_\text{i}=\frac{\text{x}_\text{i}-\text{550}}{\text{20}}$
$(f_i \times u_i)$
500-520
14 510 -2 -27
520-540
9
530 -1 -9
540-560
5
550 = A 0 0
560-580
4 570 1 4
580-600 3 590 2 6
600-620
5
610
3
15
 
$\sum\text{f}_\text{i}=40$
 
 
$\sum\text{f}_\text{i}\text{u}_\text{i}=-12$
Thus, $\text{A}=550,\ \text{h}=20$ and $\sum\text{f}_\text{i}=40,\ \sum\text{f}_\text{i}\text{u}_\text{i}=-12$
$\therefore$ Mean $\bar{\text{x}}=\text{A}+\Big[\text{h}\times\frac{\sum\text{(f}_\text{i}\times\text{u}_\text{i})}{\sum\text{f}_\text{i}}\Big]$
$550+\Big(\frac{-12}{40}\Big)$
$=500-6=544$

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