Question
If $a = 2, b = 3,$ then the value of $(a^b + b^a)^{-1}$ is:

Answer

$(a^b + b^a)^{-1}$
Put value of $a$ and $b$,
$(2^3 + 3^2)^{-1}$
$\Rightarrow (8 + 9)^{-1}$
$\Rightarrow (17)^{-1}$
$\Rightarrow\frac{1}{17}$

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