Question
If $a=3$ and $b=-2$, find the values of: $a+b^{ b } b$
✓
Answer
We have,
$a^b+b^a$
$=(3+(-2))^{3(-2)}$
$=(3-2)^{-6}$
$=(1)^{-6}=1$
$a^b+b^a$
$=(3+(-2))^{3(-2)}$
$=(3-2)^{-6}$
$=(1)^{-6}=1$
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