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Exponents Of Real Numbers Maths - Exponents Of Real Numbers

Maharashtra Board - STD 9 - Maths (MSBSHSE - English Medium). 149 questions in this chapter.

Question types

Exponents Of Real Numbers question types

149 questions across 5 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

149
Questions
5
Question groups
5
Question types
Sample Questions

Exponents Of Real Numbers questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 3MCQ(1M)1 Mark
The value of $64^{-\frac{1}{3}}\Big(64^{\frac{1}{3}}-64^{\frac{2}{3}}\Big)$ is:
  • A
    $1$
  • B
    $13$
  • ✓
    $-3$
  • D
    $-2$

Answer: C.

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Q 4MCQ(1M)1 Mark
If $\frac{3^{5\text{x}}\times81^2\times6561}{3^{2\text{x}}}$ then $x =$
  • A
    $3$
  • ✓
    $-3$
  • C
    $\frac{1}{3}$
  • D
    $-\frac{1}{3}$

Answer: B.

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Q 173 Mark Question3 Marks
Prove that:$\Big(\frac{64}{125}\Big)^{-\frac{2}{3}}+\frac{1}{\Big(\frac{256}{625}\Big)^\frac{1}{4}}+\Big(\frac{\sqrt{25}}{\sqrt[3]{64}}\Big)^0=\frac{61}{16}$
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Q 183 Mark Question3 Marks
Show that:$\Big(\frac{\text{a}^{\text{x}+1}}{\text{a}^{\text{y}+1}}\Big)^{\text{x}+\text{y}}\Big(\frac{\text{a}^{\text{y}+2}}{\text{a}^{\text{z}+2}}\Big)^{\text{y}+\text{z}}\Big(\frac{\text{a}^{\text{z}+3}}{\text{a}^{\text{x}+3}}\Big)^{\text{z}+\text{x}}=1$
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Q 224 Mark Question4 Marks
Solve the following equations:$8^{\text{x}+1}=16^{\text{y}+2}$ and $\Big(\frac{1}{2}\Big)^{3+\text{x}}=\Big(\frac{1}{4}\Big)^{3\text{y}}$
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Q 234 Mark Question4 Marks
For any positive real number x, find the value of $\Big(\frac{\text{x}^{\text{a}}}{\text{x}^{\text{b}}}\Big)^{\text{a}+\text{b}}\times\Big(\frac{\text{x}^{\text{b}}}{\text{x}^{\text{c}}}\Big)^{\text{b}+\text{c}}\times\Big(\frac{\text{x}^{\text{c}}}{\text{x}^{\text{a}}}\Big)^{\text{c}+\text{a}}$
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Q 254 Mark Question4 Marks
Simplify:$\sqrt[\text{lm}]{\frac{\text{x}^\text{l}}{\text{x}^\text{m}}}\times\sqrt[\text{mn}]{\frac{\text{x}^\text{m}}{\text{x}^\text{n}}}\times\sqrt[\text{nl}]{\frac{\text{x}^\text{n}}{\text{x}^\text{l}}}$
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