MCQ
If $A = [a\,\,b],B = [ - b - a]$ and $C = \left[ \begin{array}{l}\,\,\,\,a\\ - a\end{array} \right]$, then the correct statement is
- A$A = - B$
- B$A + B = A - B$
- ✓$AC = BC$
- D$CA = CB$
$BC = [ - b\,\,\, - a]\,\left[ \begin{array}{l}\,\,\,a\\ - a\end{array} \right] = [{a^2} - ab]$
$\therefore$ $AC = BC$.
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