MCQ
If A and B are two disjoint sets, then $\text{n(A}\cup\text{B)}$ is equal to:
- A$\text{n(A) + n(B)}$
- B$\text{n(A) + n(B)} - \text{n(A}\cap\text{B)}$
- C$\text{n(A) + n(B) + n(A}\cap\text{B)}$
- D$\text{n(A) n(B)}.$
Solution:
Two sets are disjoint if they do not have a common element in them, i.e., $\text{A}\cap\text{B}=\phi.$
$\therefore\text{n(A}\cup\text{B) = n(A) + n(B)}.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Six boys and six girls sit in a row randomly. The probability that all girls sit together is
Two lines are perpendicular if the product of their slopes is:
The number of terms with integral coefficients in the expansion of $\Big(17^{\frac{1}{3}}+35^{\frac{1}{2}}\text{x}\Big)^{600}$ is:
If f(x) = x100 + x99 ....... + x + 1, then f'(1) is equal to: