MCQ
If $A$ and $B$ are two sets then $(A -B) \cup (B -A) \cup (A \cap B)$ is equal to
- ✓$A \cup B$
- B$A \cap B$
- C$A$
- D$B'$
✓
Answer
Correct option: A.
$A \cup B$
a
(a) From Venn-Euler's diagram,
(a) From Venn-Euler's diagram,
$\therefore (A - B)\, \cup (B - A) \cup (A \cap B) = A \cup B$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The coordinates of the foci of the rectangular hyperbola $xy = {c^2}$ are
→If $\text{R}=\{(\text{x, y}):\text{x, y}\in\text{Z},\text{ x}^2+\text{y}^2\leq4\}$ is a relation on $Z,$ then the domain of $R$ is:
→If $\text{arg (z – 1) = arg (z + 3i),}$ then $x – 1 : y$ is equal to:
→The sides of a triangle are distinct positive integers in an arithmetic progression. If the smallest side is $10$, the number of such triangles is
→$\mathop {\lim }\limits_{h \to 0} \frac{{{{(a + h)}^2}\sin (a + h) - {a^2}\sin a}}{h} = $
→If $\alpha $ and $\beta $ are roots of $a{x^2} + 2bx + c = 0$, then $\sqrt {\frac{\alpha }{\beta }} + \sqrt {\frac{\beta }{\alpha }} $is equal to
→If a vertex of a triangle is $(1, 1)$ and the mid points of two sides through this vertex are $(-1, 2)$ and $(3, 2)$, then the centroid of the triangle is
→In the expansion of ${\left( {\frac{{3{x^2}}}{2} - \frac{1}{{3x}}} \right)^9}$,the term independent of $x$ is
→The value of $\cos y\cos \left( {\frac{\pi }{2} - x} \right) - \cos \left( {\frac{\pi }{2} - y} \right)\cos x$ $ + \sin y\cos \left( {\frac{\pi }{2} - x} \right) + \cos x\sin \left( {\frac{\pi }{2} - y} \right)$ is zero, if
→If $(1 + \sin A)(1 + \sin B)(1 + \sin C)$$ = (1 - \sin A)(1 - \sin B)(1 - \sin C),$ then each side is equal to
→