MCQ
If $a, b $ and $c $ are unit vectors such that $a + b - c = 0,$ then the angle between $a$ and $b$ is
- A$\pi /6$
- B$\pi /3$
- C$\pi /2$
- ✓$2\pi /3$
Using dot product, $(a + b).(a + b) = c.c$
$ \Rightarrow a.a + b.b + 2a.b = c.c$
$ \Rightarrow \,|a|.|a|\cos 0^\circ + |b|.|b|\cos 0^\circ + 2|a|.|b|\cos \alpha $
$ = \,|c|.|c|\cos 0^\circ $, $(\because \,\,\,|a|\, = \,|b|\, = \,|c|\, = 1)$
$ \Rightarrow 1 + 1 + 2\cos \alpha = 1 \Rightarrow \cos \alpha = - \frac{1}{2} \Rightarrow \alpha = \frac{{2\pi }}{3}$.
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