Question
If α, β are roots of quadratic equation,
✓
Answer
$\alpha+\beta=2, \alpha \times \beta=-\frac{3}{2}$
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Similar questions
To check the rule for the terms of the sequence look at the arrangements and fill the empty boxes suitably.
-1, -1.5, -2, -2.5,…
-1, -1.5, -2, -2.5,…
Pushpmala has invested ₹ 24,000 and purchased share of FV ₹ 20 at a premium of ₹ 4. Complete the following activity to find the number of shares she purchased.
Activity :
FV = ₹ 20
Premium = ₹ 4
MV = FV + ⬜
= 20 + ⬜
= ₹ 24
$\text { Number of shares } = \frac{\text { Total investmen }}{ MV } $
$=\frac{24,000}{\square}$
= ⬜ shares.
→Activity :
FV = ₹ 20
Premium = ₹ 4
MV = FV + ⬜
= 20 + ⬜
= ₹ 24
$\text { Number of shares } = \frac{\text { Total investmen }}{ MV } $
$=\frac{24,000}{\square}$
= ⬜ shares.
To check the rule for the terms of the sequence look at the arrangements and fill the empty boxes suitably.
6,12,18,24,…
6,12,18,24,…
One of the roots of the quadratic equation $5 m^2+2 m+k=1$ is $-\frac{7}{5}$. Complete the following activity to find the value of k :
→Complete the following activity to find the length of hypotenuse of right angled triangle, if sides of right angle are $9 cm$ and $12 cm$.
Activity: In $\triangle P Q R, m \angle P Q R=90^{\circ}$
By Pythagoras Theorem,
$P Q^2+\square=P R^2$
$\therefore P R^2=9^2+12^2$
$\therefore P R^2=\square+144$
$\therefore P R^2=\square$
$\therefore P R=15$
$\therefore$ Length of hypotenuse of triangle PQR is $\square cm$.
→→Activity: In $\triangle P Q R, m \angle P Q R=90^{\circ}$
By Pythagoras Theorem,
$P Q^2+\square=P R^2$
$\therefore P R^2=9^2+12^2$
$\therefore P R^2=\square+144$
$\therefore P R^2=\square$
$\therefore P R=15$
$\therefore$ Length of hypotenuse of triangle PQR is $\square cm$.
Complete the following table to draw the graph of $2x – 6y = 3$
→Write the correct number in the given boxes from the following A. P.
1, 8, 15, 22, . . .
Here
a = ⬜, $t _1$ = ⬜, $t _2$ = ⬜, $t _3$ = ⬜
$t _2- t _1$ = ⬜ - ⬜ = ⬜
$t _3- t _2$ = ⬜ - ⬜ = ⬜
∴ d = ⬜
→→→1, 8, 15, 22, . . .
Here
a = ⬜, $t _1$ = ⬜, $t _2$ = ⬜, $t _3$ = ⬜
$t _2- t _1$ = ⬜ - ⬜ = ⬜
$t _3- t _2$ = ⬜ - ⬜ = ⬜
∴ d = ⬜
