Question
If $a, b, c$, are in G.P., prove that the following are also in G.P. $\text{a}^2+\text{b}^2,\text{ab}+\text{bc},\text{b}^2+\text{c}^2$

Answer

a, b, c are in G.P. $a, b = ar, c = ar^2 (\text{ab}+\text{bc})^2=\big(\text{a}^2+\text{b}^2\big)\big(\text{b}^2+\text{c}^2\big)$
$\Big(\text{a}\times\text{ar}+\text{ar}\times\text{ar}^2\big)^2\big(\text{a}^2+(\text{ar})^2\big)\big((\text{ar})^2+\big(\text{ar}^2\big)^2\Big)$
$\big(\text{a}^2\text{r}+\text{a}^2\text{r}^3\big)^2=\big(\text{a}^2+\text{a}^2\text{r}^2\big)\big(\text{a}^2\text{r}^2+\text{a}^2\text{r}^4\big)$
$\text{a}^4\big(\text{r}+\text{r}^3\big)^2=\text{a}^4\big(1+\text{r}^2\big)\big(\text{r}^2+\text{r}^4\big)$
$\text{a}^4\big(\text{r}+\text{r}^2\big)^2=\text{a}^4\big(1+\text{r}^2\big)\text{r}^2\big(1+\text{r}^2\big)$
$\text{a}^4\text{r}^2\big(1+\text{r}^2\big)^2=\text{a}^4\big(1+\text{r}^2\big)\text{r}^2\big(1+\text{r}^2\big)$
$\text{a}^4\text{r}^2\big(1+\text{r}^2\big)^2=\text{a}^4\text{r}^2\big(1+\text{r}^2\big)$
$\text{L.H.S}=\text{R.H.S}$
$\Rightarrow(\text{ab}+\text{bc})^2=\big(\text{a}^2+\text{b}^2\big)\big(\text{b}^2+\text{c}^2\big)$
$\Rightarrow\big(\text{a}^2+\text{b}^2\big),(\text{ab}+\text{bc}),\big(\text{b}^2+\text{c}^2\big)\text{ are in G.P.}$

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