Question
Evaluate the following limit: $\lim\limits_{\text{x}\rightarrow1}\frac{\text{x}^7-2\text{x}^5+1}{\text{x}^3-3\text{x}^2+2}$

Answer

$\lim\limits_{\text{x}\rightarrow1}\frac{\text{x}^7-2\text{x}^5+1}{\text{x}^3-3\text{x}^2+2}$ $=\lim\limits_{\text{x}\rightarrow1}\frac{(\text{x}-1)\big(\text{x}^6+\text{x}^5-\text{x}^4-\text{x}^3-\text{x}^2-\text{x}-1\big)}{(\text{x}-1)\big(\text{x}^2-2\text{x}-2\big)}$ $= \lim\limits_{\text{x}\rightarrow1}\frac{\big(\text{x}^6+\text{x}^5-\text{x}^4-\text{x}^3-\text{x}^2-\text{x}-1\big)}{\big(\text{x}^2-2\text{x}-2\big)}$ $=\frac{(1+1-1-1-1-1-1)}{(1-2-2)}$ $=\frac{-3}{-3}$ $=1$

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