MCQ
If $A + B + C = \pi \,(A,B,C > 0)$ and the angle $C$ is obtuse then
- A$\tan A\,\tan B > 1$
- ✓$\tan A\,\tan B < 1$
- C$\tan A\,\,\tan B = 1$
- DNone of these
$ \Rightarrow \tan (A + B) = \tan (\pi - C)$
$ \Rightarrow \frac{{\tan A + \tan B}}{{1 - \tan A\tan C}} = \tan (\pi - C)$
$ \Rightarrow \frac{{\tan A + \tan B}}{{1 - \tan A\tan B}} = - \tan C$
Now $C$ is an obtuse angle, hence
$ \Rightarrow \tan C < 0 \Rightarrow - \tan C > 0$
$ \Rightarrow \frac{{\tan A + \tan B}}{{1 - \tan A\tan B}} > 0$
$\Rightarrow 1 - \tan A\tan B > 0$
$(\because A,B$ are acute angles; $\therefore \tan A > 0,\tan B > 0 )$
$ \Rightarrow \tan A\tan B < 1$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.