MCQ
If $A + B + C = \pi \,(A,B,C > 0)$ and the angle $C$ is obtuse then
  • A
    $\tan A\,\tan B > 1$
  • $\tan A\,\tan B < 1$
  • C
    $\tan A\,\,\tan B = 1$
  • D
    None of these

Answer

Correct option: B.
$\tan A\,\tan B < 1$
b
(b) $A + B + C = \pi \Rightarrow A + B = \pi - C$

$ \Rightarrow \tan (A + B) = \tan (\pi - C)$ 

$ \Rightarrow \frac{{\tan A + \tan B}}{{1 - \tan A\tan C}} = \tan (\pi - C)$

$ \Rightarrow \frac{{\tan A + \tan B}}{{1 - \tan A\tan B}} = - \tan C$ 

Now $C$ is an obtuse angle, hence 

$ \Rightarrow \tan C < 0 \Rightarrow - \tan C > 0$

$ \Rightarrow \frac{{\tan A + \tan B}}{{1 - \tan A\tan B}} > 0$

$\Rightarrow 1 - \tan A\tan B > 0$

$(\because A,B$ are acute angles; $\therefore \tan A > 0,\tan B > 0 )$

$ \Rightarrow \tan A\tan B < 1$.

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