Question
If $(a + b + c)(a – b + c) = a2 + b2 + c2$, show that $a, b, c$ are in continued proportion.

Answer

$(a + b + c)(a – b + c) = a^2 + b^2 + c^2 …$[Given]
$\therefore a(a – b + c) + b(a – b + c) + c(a – b + c) = a2 + b2 + c2$
$\therefore a^2 – ab + ac + ab – b^2 + be + ac – be + c^2 = a^2 + b^2 + c^2$
$\therefore a^2 + 2ac – b^2 + c^2 = a^2 + b^2 + c^2$
$\therefore 2ac – b^2 = b^2$
$\therefore 2ac = 2b^2$
$\therefore ac = b^2$
$\therefore b^2 = ac$
$\therefore a, b, c$ are in continued proportion.

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