MCQ
If a drunkard person tries to take a step, then it will be a forward or backward step with probabilities $\frac{1}{4},\frac{1}{2}$ respectively, or he will remain in 'as it is' position. If he tries to take a step $5$ times, then probability that he will be one step away from the initial position
- A$\frac {210}{2^8}$
- ✓$\frac {315}{2^{10}}$
- C$\frac {171}{2^{16}}$
- D$\frac {75}{2^8}$