If A is a singular matrix, then adj A is. 1. non−singular 2. sing… - Vidyadip

Question

If A is a singular matrix, then adj A is.

non−singular
singular
symmetric
not defined

✓

Answer

singular

Solution:
Given ∣A∣ = 0
We know ∣adjA∣ = ∣A∣ n - 1
∴ ∣adjA∣ = 0
Hence, adj A is singular

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from DETERMINANTS→DETERMINANTS — all question types→MATHS STD 12 Science question papers→Rajasthan Board STD 12 Science question papers→Rajasthan Board question paper generator→

Similar questions

If A, B are square matrices of order 3, A is non-singular and AB = 0, then B is a:

Null matrix.
Singular matrix.
Unit-matrix.
Non-singular matrix.

If the constraints in a linear programming problem are changed:

Solution is not defined.
The objective function has to be modified.
The problems is to be re - evaluated.
None of these.

If $\vec{\text{a}}\text{ and }\vec{\text{b}}$ are two collinear vectors, then which of the follwoing are incorrect?

$\vec{\text{b}}=\lambda\vec{\text{a}}$ for some scalar $\lambda$
$\vec{\text{a}}=\pm\vec{\text{b}}$
The respective components of $\vec{\text{a}}\text{ and }\vec{\text{b}}$ are proportional.
Both the vectors $\vec{\text{a}}\text{ and }\vec{\text{b}}$ have the same direction but different magnitudes.

Let $\vec{\text{a}}$ and $\vec{\text{b}}$ be two unit vectors and a be the angle between them. Then, $\vec{\text{a}}+\vec{\text{b}}$ is a unit vector if:

$\text{a}=\frac{\pi}{4}$
$\text{a}=\frac{\pi}{3}$
$\text{a}=\frac{2\pi}{3}$
$\text{a}=\frac{\pi}{2}$

Refer to Question 18 (Maximum value of Z+ Minimum value of Z) is equal to:

If the polynomial equation $\text{a}_0\text{x}^{\text{n}}+\text{a}_{\text{n}-1}\text{x}^{\text{n}-1}+\text{a}_{\text{n}-2}\text{x}^{\text{n}-2}+...\text{a}_2\text{x}^2+\text{a}_1\text{x}+\text{a}_0=0$ n positive integer,has two different real roots $\alpha$ and $\beta,$ then between $\alpha$ and $\beta,$ the equation $\text{n}\text{a}_{\text{n}}\text{x}^{\text{n}-1}+(\text{n}-1)\text{a}_{\text{n}-1}\text{x}^{\text{n}-2}+...+\text{a}_1=0$ has:

Exactly one root.
Almost one root.
At least one root.
No root.

If $\frac{\text{dy}}{\text{dt}}=\text{ky}$ and $\text{k}\neq0$ which of the following could be the equation of $y:$

The equation $x^2- x - 2 = 0$ in three dimensional space is represented by$:$

The binary operation $^*$ is defined by $a ^* b = a^2 + b^2 + ab + 1,$ then $(2 ^* 3) ^* 2$ is equal to$:$

$\int\limits^{\frac{\pi}{3}}_{\frac{\pi}{6}}\frac{1}{1+\sqrt{\cot\text{x}}}\text{ dx}$ is:

$\frac{\pi}{3}$
$\frac{\pi}{6}$
$\frac{\pi}{12}$
$\frac{\pi}{2}$