If a particle of charge {10^{ - 12}},coulomb moving along the hat x - direction with a velocity {10^5},m/s experiences a force of {10^{ -

Q: If a particle of charge ${10^{ - 12}}\,coulomb$ moving along the $\hat x - $ direction with a velocity ${10^5}\,m/s$ experiences a force of ${10^{ - 10}}\,newton$ in $\hat y - $ direction due to magnetic field, then the minimum magnetic field is

d (d) $F = qvB\sin \theta $ $==>$ $B = \frac{F}{{qv\sin \theta }}$ ${B_{\min }} = \frac{F}{{qv}}$(when $\theta$ = $90^o$) $\therefore \;{B_{\min }} = \frac{F}{{qv}} = \frac{{{{10}^{ - 10}}}}{{{{10}^{ - 12}} \times {{10}^5}}} = {10^{ - 3}}$ $Tesla$ in $U = \frac{{{B^2}}}{{2{\mu _0}}},$ $\hat z - $ direction.

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

If a particle of charge ${10^{ - 12}}\,coulomb$ moving along the $\hat x - $ direction with a velocity ${10^5}\,m/s$ experiences a force of ${10^{ - 10}}\,newton$ in $\hat y - $ direction due to magnetic field, then the minimum magnetic field is

A$6.25 \times {10^3}\,tesla$ in $\hat z - $ direction
B${10^{ - 15}}\,tesla$ in $\hat z - $ direction
C$6.25 \times {10^{ - 3}}\,tesla$ in $\hat z - $ direction
D${10^{ - 3}}\,tesla$ in $\hat z - $ direction

Medium

STD 11 Science
NEET
STD 12 - 4. Moving charges and magnetism
Physics

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