What is the magnetic field at a distance $R$ from a coil of radius $r$ carrying current $I$ ?
AIIMS 2007, Medium
Download our app for free and get started
The magnetic field is $B = \frac{{{\mu _0}I{r^2}}}{{2{{({R^2} + {r^2})}^{\frac{3}{2}}}}}$
(see application of Biot-Savart law to magnetic field at a point along axis of coil)
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1An arrangement with a pair of quarter circular coils of radii $r$ and $R$ with a common centre $C$ and carrying a current $I$ is shown in the figure. The permeability of free space is $\mu_0$. The magnetic field at $C$ isView Solution
- 2View SolutionA charged particle moving in a magnetic field experiences a resultant force
- 3An electron with kinetic energy $5 \mathrm{eV}$ enters a region of uniform magnetic field of $3 \mu \mathrm{T}$ perpendicular to its direction. An electric field $\mathrm{E}$ is applied perpendicular to the direction of velocity and magnetic field. The value of $\mathrm{E}$, so that electron moves along the same path, is . . . . . $\mathrm{NC}^{-1}$.View Solution
(Given, mass of electron $=9 \times 10^{-31} \mathrm{~kg}$, electric charge $=1.6 \times 10^{-19} \mathrm{C}$ )
- 4If the strength of the magnetic field produced $10\,cm$ away from a infinitely long straight conductor is ${10^{ - 5}}\,Weber/{m^2}$, the value of the current flowing in the conductor will be........$ampere$View Solution
- 5View SolutionThe direction of magnetic lines of forces close to a straight conductor carrying current will be
- 6A solenoid is $1.0$ $ metre$ long and it has $4250$ $turns$. If a current of $5.0$ $ampere$ is flowing through it, what is the magnetic field at its centre $[{\mu _0} = 4\pi \times {10^{ - 7}}\,weber/amp - m]$View Solution
- 7View SolutionWhat is the net force on the square coil
- 8A long copper tube of inner radius $R$ carries a current $i$. The magnetic field $B$ inside the tube isView Solution
- 9A beam of protons with speed $4 \times 10^{5}\, ms ^{-1}$ enters a uniform magnetic field of $0.3\, T$ at an angle of $60^{\circ}$ to the magnetic field. The pitch of the resulting helical path of protons is close to....$cm$View Solution
(Mass of the proton $=1.67 \times 10^{-27}\, kg$, charge of the proton $=1.69 \times 10^{-19}\,C$)
- 10A straight wire of diameter $0.5\, mm$ carrying a current of $1\, A$ is replaced by another wire of $1\, mm$ diameter carrying the same current. The strength of magnetic field far away isView Solution