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A copper wire of resistance $R$ is cut into ten parts of equal length. Two pieces each are joined in series and then five such combinations are joined in parallel. The new combination will have a resistance
Water boils in an electric kettle in $15\,\min$ after switching on. If the length of the heating wire is decreased to $2/3$ of its initial value, then the same amount of water will boil with the same supply voltage in ............. $min$
In a typical Wheatstone network, the resistances in cyclic order are $A = 10 \,\Omega $, $B = 5 \,\Omega $, $C = 4 \,\Omega $ and $D = 4 \,\Omega $ for the bridge to be balanced
Variation of current passing through a conductor as the voltage applied across its ends as varied is shown in the adjoining diagram. If the resistance $(R)$ is determined at the points $A$, $B$, $C$ and $D$, we will find that
Four identical electrical lamps are labelled $1.5\,V$, $0.5\,A$ which describes the condition necessary for them to operate at normal brightness. A $12\,V$ battery of negligible internal resistance is connected to lamps as shown, then
There is a current of $1.344\, amp$ in a copper wire whose area of cross-section normal to the length of the wire is $1\,m{m^2}$. If the number of free electrons per $c{m^3}$ is $8.4 \times {10^{22}}$, then the drift velocity would be