MCQ
If a straight line $APQB$ is drawn to cut two concentric circles, then:


- A$AP >> BQ$
- B$AP << BQ$
- ✓$AP = BQ$
- D$AQ >> PB$


Let $OD$ is perpendicular to $AB.$ Then $AD = DB.$
Also $DP = DQ$
Therefore, $AP = AD - PD$
$= BD - DQ$
$= BQ$
Hence, $AP = BQ$
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