Question
If a triangle having sides 50 cm., 14 cm, and 48 cm., then state wheather given triangle is right angled triangle or not.
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Answer
The sides of the triangle are $50 \mathrm{~cm}, 14 \mathrm{~cm}$ and $48 \mathrm{~cm}$.
The longest side of the triangle is $50 \mathrm{~cm}$.
$\therefore(50)^2=2500$
Now, sum of the squares of the remaining sides is,
$(14)^2+(48)^2=196+2304=2500$
$\therefore(50)^2=(14)^2+(48)^2$
$\therefore$ Square of the longest side is equal to the sum of the squares of the remaining two sides.
$\therefore$ The given sides will form a right angled triangle. ...[Converse of Pythagoras theorem]
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