- ✓$\alpha - \frac{5}{4}$
- B$\alpha - \frac{1}{2}$
- C$\alpha - 2$
- D$\alpha + \frac{5}{4}$
$\alpha - \frac{7}{2},\alpha - 3,\alpha - \frac{5}{2},\alpha - 2,\alpha - \frac{1}{2},\alpha + \frac{1}{2},\alpha + 4,\alpha + 5$
Median $ = \frac{1}{2}[{\rm{value\ of\ }}{{\rm{4}}^{{\rm{th}}}}{\rm{\ item}} + {\rm{value \ of\ }}{{\rm{5}}^{{\rm{th}}}}{\rm{\ item]}}$
Median $ = \frac{{\alpha - 2 + \alpha - \frac{1}{2}}}{2}$
$ = \frac{{2\alpha - \frac{5}{2}}}{2}$= $\alpha - \frac{5}{4}$.
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$\lim _{x \rightarrow 0^{+}} \frac{(1-x)^{\frac{1}{x}}-e^{-1}}{x^a}$
is equal to a nonzero real number, is. . . . . . .
$[A]$ $\tan \left(\frac{\alpha}{2}\right)+\sqrt{3} \tan \left(\frac{\beta}{2}\right)=0$
$[B]$ $\sqrt{3} \tan \left(\frac{\alpha}{2}\right)+\tan \left(\frac{\beta}{2}\right)=0$
$[C]$ $\tan \left(\frac{\alpha}{2}\right)-\sqrt{3} \tan \left(\frac{\beta}{2}\right)=0$
$[D]$ $\sqrt{3} \tan \left(\frac{\alpha}{2}\right)-\tan \left(\frac{\beta}{2}\right)=0$