Question
If $A=\left[\begin{array}{cc}2 & -3 \\ 5 & -4 \\ -6 & 1\end{array}\right], B=\left[\begin{array}{cc}-1 & 2 \\ 2 & 2 \\ 0 & 3\end{array}\right]$ and $C=\left[\begin{array}{cc}4 & 3 \\ -1 & 4 \\ -2 & 1\end{array}\right]$

Show that

i. A+B=B+A

ii. (A + B) + C = A + (B + C)

Answer

$A+B=\left[\begin{array}{cc}2 & -3 \\ 5 & -4 \\ -6 & 1\end{array}\right]+\left[\begin{array}{cc}-1 & 2 \\ 2 & 2 \\ 0 & 3\end{array}\right]$

$=\left[\begin{array}{cc}2-1 & -3+2 \\ 5+2 & -4+2 \\ -6+0 & 1+3\end{array}\right]$

$\therefore \quad A+B=\left[\begin{array}{cc}1 & -1 \\ 7 & -2 \\ -6 & 4\end{array}\right]$

....(i)

$B+A=\left[\begin{array}{cc}-1 & 2 \\ 2 & 2 \\ 0 & 3\end{array}\right]+\left[\begin{array}{cc}2 & -3 \\ 5 & -4 \\ -6 & 1\end{array}\right]$

$=\left[\begin{array}{cc}-1+2 & 2-3 \\ 2+5 & 2-4 \\ 0-6 & 3+1\end{array}\right]$

$\therefore \quad B+A=\left[\begin{array}{cc}1 & -1 \\ 7 & -2 \\ -6 & 4\end{array}\right]$

From (i) and (ii), we get A + B = B + A

$(A+B)+C=\left\{\left[\begin{array}{cc}2 & -3 \\ 5 & -4 \\ -6 & 1\end{array}\right]+\left[\begin{array}{cc}-1 & 2 \\ 2 & 2 \\ 0 & 3\end{array}\right]\right\}+\left[\begin{array}{cc}4 & 3 \\ -1 & 4 \\ -2 & 1\end{array}\right]$

$=\left[\begin{array}{cc}2-1 & -3+2 \\ 5+2 & -4+2 \\ -6+0 & 1+3\end{array}\right]+\left[\begin{array}{cc}4 & 3 \\ -1 & 4 \\ -2 & 1\end{array}\right]$

$=\left[\begin{array}{cc}1 & -1 \\ 7 & -2 \\ -6 & 4\end{array}\right]+\left[\begin{array}{cc}4 & 3 \\ -1 & 4 \\ -2 & 1\end{array}\right]$

$=\left[\begin{array}{cc}1+4 & -1+3 \\ 7-1 & -2+4 \\ -6-2 & 4+1\end{array}\right]$

$\therefore \quad(\mathrm{A}+\mathrm{B})+\mathrm{C}=\left[\begin{array}{cc}5 & 2 \\ 6 & 2 \\ -8 & 5\end{array}\right]$

$\ldots$...(i)

$\begin{aligned} A+(B+C) & =\left[\begin{array}{cc}2 & -3 \\ 5 & -4 \\ -6 & 1\end{array}\right]+\left\{\left[\begin{array}{cc}-1 & 2 \\ 2 & 2 \\ 0 & 3\end{array}\right]+\left[\begin{array}{cc}4 & 3 \\ -1 & 4 \\ -2 & 1\end{array}\right]\right\} \\ & =\left[\begin{array}{cc}2 & -3 \\ 5 & -4 \\ -6 & 1\end{array}\right]+\left[\begin{array}{cc}-1+4 & 2+3 \\ 2-1 & 2+4 \\ 0-2 & 3+1\end{array}\right] \\ & =\left[\begin{array}{cc}2 & -3 \\ 5 & -4 \\ -6 & 1\end{array}\right]+\left[\begin{array}{cc}3 & 5 \\ 1 & 6 \\ -2 & 4\end{array}\right]\end{aligned}$

$=\left[\begin{array}{cc}2+3 & -3+5 \\ 5+1 & -4+6 \\ -6-2 & 1+4\end{array}\right]$

$=\left[\begin{array}{cc}5 & 2 \\ 6 & 2 \\ -8 & 5\end{array}\right]$

..(ii)

$(A+B)+C=A+(B+C)$

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