MCQ
If $A=\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right]$, then $A^2=$
  • A
    $\left[\begin{array}{ll}2 & 0 \\ 1 & 1\end{array}\right]$
  • B
    $\left[\begin{array}{ll}1 & 0 \\ 1 & 2\end{array}\right]$
  • C
    $\left[\begin{array}{ll}1 & 0 \\ 2 & 1\end{array}\right]$
  • none of these

Answer

Correct option: D.
none of these
Given
$
\begin{aligned}
& A=\left[\begin{array}{ll}
1 & 0 \\
1 & 1
\end{array}\right] \\
& A^2=A \times A=\left[\begin{array}{ll}
1 & 0 \\
1 & 1
\end{array}\right] \times\left[\begin{array}{ll}
1 & 0 \\
1 & 1
\end{array}\right] \\
& =\left[\begin{array}{ll}
1+0 & 0+0 \\
1+1 & 0+1
\end{array}\right] \\
& =\left[\begin{array}{ll}
1 & 0 \\
2 & 1
\end{array}\right] . \\
&
\end{aligned}
$

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