Question
If $A=\left[\begin{array}{ll}2 & -1 \\ 3 & -2\end{array}\right]$, find $A^3$.
$\therefore \mathrm{A}^2=1$
Multiplying throughout by A, we get
$\begin{aligned} & A^3=A .1 \\ & \therefore A^3=A\end{aligned}$
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$A=\left[\begin{array}{ccc}2 & -6 & 1 \\ -4 & 0 & 5\end{array}\right]$