MCQ

Share

If $\alpha \in \left( {0,\,\frac{\pi }{2}} \right),$ then $\sqrt {{x^2} + x} + \frac{{{{\tan }^2}\alpha }}{{\sqrt {{x^2} + x} }}$ is always greater than or equal to

• ✓
  $2\,\,\tan \alpha $
• B
  $1$
• C
  $2$
• D
  ${\sec ^2}\alpha $