MCQ
If $\alpha+\beta+\text{y}=2\text{p},$ then:
- ✓$\frac{\tan\alpha}{2}+\frac{\tan\beta}{2}+\frac{\tan\text{y}}{2}=\frac{\tan\alpha}{2}.\frac{\tan\beta}{2}.\frac{\tan{\text{y}}}{2}$
- B$\frac{\tan\alpha}{2}.\frac{\tan{\beta}}{2}+\frac{\tan{\beta}}{2}.\frac{\tan{\text{y}}}{2}=\frac{\tan\text{y}}{2}.\frac{\tan{\alpha}}2=1{}$
- C$\frac{\tan\alpha}{2}+\frac{\tan\beta}{2}+\frac{\tan\text{y}}{2}=\frac{\tan\alpha}{2}.\frac{\tan\beta}{2}.\frac{\tan\text{y}}{2}$
- D$\text{None of these}$