MCQ
If $\alpha+\beta+\text{y}=2\text{p},$ then:
  • $\frac{\tan\alpha}{2}+\frac{\tan\beta}{2}+\frac{\tan\text{y}}{2}=\frac{\tan\alpha}{2}.\frac{\tan\beta}{2}.\frac{\tan{\text{y}}}{2}$
  • B
    $\frac{\tan\alpha}{2}.\frac{\tan{\beta}}{2}+\frac{\tan{\beta}}{2}.\frac{\tan{\text{y}}}{2}=\frac{\tan\text{y}}{2}.\frac{\tan{\alpha}}2=1{}$
  • C
    $\frac{\tan\alpha}{2}+\frac{\tan\beta}{2}+\frac{\tan\text{y}}{2}=\frac{\tan\alpha}{2}.\frac{\tan\beta}{2}.\frac{\tan\text{y}}{2}$
  • D
    $\text{None of these}$

Answer

Correct option: A.
$\frac{\tan\alpha}{2}+\frac{\tan\beta}{2}+\frac{\tan\text{y}}{2}=\frac{\tan\alpha}{2}.\frac{\tan\beta}{2}.\frac{\tan{\text{y}}}{2}$
  1. $\frac{\tan\alpha}{2}+\frac{\tan\beta}{2}+\frac{\tan\text{y}}{2}=\frac{\tan\alpha}{2}.\frac{\tan\beta}{2}.\frac{\tan{\text{y}}}{2}$

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