MCQ
If an $\alpha$-particle and a proton are accelerated from rest by a potential difference of 1 megavolt then the ratio of their kinetic energy will be
  • A
    $\frac{1}{2}$
  • B
    $1$
  • $2$
  • D
    $4$

Answer

Correct option: C.
$2$
c
(c)

$\Delta K E=q V$

$\frac{\Delta KE _\alpha}{\Delta KE _p}=\frac{q_\alpha V}{q_p V}=\frac{q_\alpha}{q_p}=2$

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