If an average person jogs, he produces 14.5 103 cal/ min. This is… - Vidyadip

MCQ

If an average person jogs, he produces $14.5 \times 103\ \text{cal/ min.}$ This is removed by the evaporation of sweat. The amount of sweat evaporated per minute $($assuming $1\ kg$ requires $580 \times 103\ \text{cal}$ for evaparation$)$ is

✓
$0.25\ kg$
B
$2.25\ kg$
C
$0.05\ kg$
D
$0.20\ kg$

✓

Answer

Correct option: A.

$0.25\ kg$

$580 \times 10^3$ Calories are needed to convert $1\ \ce{kg H_2O}$ into steam.
$1\ \text{cal}$ will producer sweat $=\frac{1}{580\times10^{3}}$
$14.5 \times 10^3\ \text{cal}$ will producer sweat $=\frac{14.5\times10^3}{580\times10^3}$
$=\frac{145}{5800}\text{kg }$ Perminute
$=0.25\text{kg }$ Perminute

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