MCQ
If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by ( $c$ is speed of light)
  • A
    $\frac{3 R c}{29}$
  • $\frac{5 R c}{36}$
  • C
    $\frac{7 R c}{36}$
  • D
    $\frac{8 R c}{31}$

Answer

Correct option: B.
$\frac{5 R c}{36}$
b
(b)

$\frac{1}{\lambda}=R\left(\frac{1}{2^2}-\frac{1}{3^2}\right)$

$f=R_0 c\left(\frac{1}{4}-\frac{1}{9}\right)$

$f=\frac{R c 5}{36}=\frac{5 R c}{36}$

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