If an electron is accelerated by 8.8 10^ 14 m / s ^2 , then elect… - Vidyadip

MCQ

If an electron is accelerated by $8.8 \times 10^{14} m / s ^2$ , then electric field required for acceleration is $($given specific charge of the electron $=1.76 \times 10^{11} Ckg ^{-1} )Z$

A
$52 V cm ^{-1}$
✓
$50 V cm ^{-1}$
C
$54 V cm ^{-1}$
D
$56 V cm ^{-1}$

✓

Answer

Correct option: B.

$50 V cm ^{-1}$

$a=8.8 \times 10^{14} m / s ^2$
$\frac{e}{m}=1.76 \times 10^{11} C^{-1} \ kg^{-1}$
$a=\frac{F}{m}=\frac{e E}{m}=\left(\frac{e}{m}\right) E$
$8.8 \times 10^{14}=1.76 \times 10^{11} \times E$
$E=\frac{8.8 \times 10^{14}}{1.76 \times 10^{11}}$
$=5000 Vm ^{-1}$
$=50 Vcm ^{-1}$

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